Battery or electrochemical cell
Explanation:
A battery is a power source that directs electrons from oxidation - reduction reactions to flow through a device to give electrical power.
- A battery is an electrochemical cell.
- Electrochemical cells are devices in which chemical reactions produce an electric current that is, chemical energy is turned into electrical energy.
- The reactions here are spontaneous redox reactions, hence electrons flows on its own in an external circuit.
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Battery brainly.com/question/8892837
Atomic battery brainly.com/question/6457557
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Answer:
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
Explanation:

Taking natural logarithm on both the sides:
![\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)]](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D-%5Cln%5B2%5D%3D%5Cln%20%5Bb%5D-%5Cln%20%5B%28x-2%29%5D)
![\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)]](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D%3D%5Cln%5B2%5D%2B%5Cln%20%5Bb%5D-%5Cln%20%5B%28x-2%29%5D)
![\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)]](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D%3D%5Cln%20%7B%5B2%5Ctimes%20b%5D-%5Cln%20%5B%28x-2%29%5D)
Slope intercept form is generally given as:

m = slope, c = intercept on y axis or vertical axis
On rearranging equation:
![\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}](https://tex.z-dn.net/?f=%5Cln%20%5B%28y%2B3%29%5D%3D%28-1%29%5Ctimes%20%5Cln%20%5B%28x-2%29%5D%2B%5Cln%20%7B2b%7D)
y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b
(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.
OPTION B & C are the answers....
The answer is atomic radii; the size or radii of an atom increases from left to right, versus the ionization energies and electronegativities of atoms which increase from right to left.
Answer:
t = 7.58 * 10¹⁹ seconds
Explanation:
First order rate constant is given as,
k = (2.303
/t) log [A₀]
/[Aₙ]
where [A₀] is the initial concentraion of the reactant; [Aₙ] is the concentration of the reactant at time, <em>t</em>
[A₀] = 615 calories;
[Aₙ] = 615 - 480 = 135 calories
k = 2.00 * 10⁻²⁰ sec⁻¹
substituting the values in the equation of the rate constant;
2.00 * 10⁻²⁰ sec⁻¹ = (2.303/t) log (615/135)
(2.00 * 10⁻²⁰ sec⁻¹) / log (615/135) = (2.303/t)
t = 2.303 / 3.037 * 10⁻²⁰
t = 7.58 * 10¹⁹ seconds