Ask question

Ask question

All categories

3 years ago

12

I just need answers please!!

2 answers:

otez555 [7]3 years ago

4 0

Answer:

#1 is an organism

#2 is cell

#4 - Digestive System gets nutrients (good) from food and hands it over to the blood and Circulatory System then carries those nutrients where they need to go

evablogger [386]3 years ago

4 0

Answer:

Now i can add a real answer

Explanation:

1: if you think about it you are made up of organs. and then other people will describe yoou as an organism Answer is organism

2:Smallest to biggest= cell-tissue-organ-organism

4:Circulatory/Cardiovascular System through the blood to most parts of the body provides nutrients and oxygen which is needed for our bodies to have ENERGY!

Citation= https://www.joliet86.org/assets/1/6/BODYSYSTEMNotes.pdf

You might be interested in

Someone help me pleasee?

Kamila [148]

Maybe its the second one

7 0

3 years ago

The wavelength of a light wave can be used to measure which of the following

Tema [17]

Wavelength is the distance between crests of the wave.

4 0

3 years ago

Characterize EACH of the three given statements as being TRUE or FALSE and then indicate the collective true-false status of the

Aleks04 [339]

Answer:

A = True

B = False

C = True.

I think this is the answer

8 0

3 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

Nata [24]

Answer:

The correct answer is option B.

Explanation:

$3NaOH+2NBr_3\rightarrow 3HOBr+3NaBr+N_2$

Moles of $NBr_3$ = 40 mol

Moles of NaOH = 48 mol

According to reaction, 3 moles of NaOH reacts with 2 moles $NBr_3$

Then ,48 moles of NaOH will reacts with:

$\frac{2}{3}\times 48 mol=32 mol$ of $NBr_3$

Then ,40 moles of $NaBr_3$ will reacts with:

$\frac{3}{2}\times 40 mol=60 mol$ of NaOH

As we can see that 48 moles of sodium will completey react with 32 moles of nitrogen tribromide.

Moles left after reaction = 40 mol - 32 mol = 8 mol

Hence, the $NBr_3$ is an excessive reagent.

6 0

3 years ago

Read 2 more answers

4vir4ik [10]

Answer: 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles$

The balanced chemical reaction is:

$2AuCl_3\rightarrow 2Au+3Cl_2$

According to stoichiometry :

2 moles of $AuCl_3$ produce = 3 moles of $Cl_2$

Thus 0.242 moles of will produce= $\frac{3}{2}\times 0.242=0.363mol$ of $Cl_2$

Mass of $Cl_2$ = $moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g$

Thus 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

5 0

3 years ago