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netineya [11]
3 years ago
15

What chemical change occurs when a more reactive substance replaces a less reactive substance in a compound?

Chemistry
1 answer:
zhuklara [117]3 years ago
5 0
I Would Pick B. Displacement For The Answer.
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What can be dissolve by water
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C. All of them can be dissolved because, they are all solvents.
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4 years ago
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Brainliest if CORRECT<br><br><br><br><br><br><br> 11
Klio2033 [76]

Answer:

Model B

Explanation:

Model A shows that light has been reflected, whereas Model B shows the light has been refracted. Light will be refracted as the light enters a more dense medium (glass), from a less dense medium (air).

This website has a really useful, thorough explanation for why this occurs:

(Check the explanation under the heading 'Explaining refraction - Higher')

https://www.bbc.co.uk/bitesize/guides/zw42ng8/revision/2

Hope this helps!

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Round each number to three significant figures. 0.036549:
valina [46]

Answer:

0.0365

Explanation:

Three significant figures after the decimal include all numbers except the zeros before other numbers.

For example 0.000003431232 to three significant figures would be 0.00000343. However if the numbers are before the decimal, the zeros are included, for example 19828300 to three significant numbers would be 19800000.

8 0
3 years ago
Sodium has an atomic number of 11 and has a net charge of 0. When sodium combines with chlorine, it has a net charge of +1. Why?
Mamont248 [21]

Answer: Option (A) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}.

In order to gain stability, sodium loses one electron and hence it forms a positive ion (Na^{+}).

Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.

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The Ksp for Cu(OH)2 is 4.8 × 10-20. Determine the molar solubility of Cu(OH)2 in a buffer solution with a pH of 10.1.
Papessa [141]

Answer:

E) 3.0x10⁻¹²

Explanation:

Ksp of Cu(OH)₂ is defined as:

Cu(OH)₂(s) ⇄ Cu²⁺(aq) + 2 OH⁻(aq)

Ksp = [Cu²⁺] [OH⁻]²

When pH is 10.1,  [OH⁻] is:

pOH = 14 - pH

pOH = 3.9

pOH = -log [OH⁻]

<em>[OH⁻] = 1.26x10⁻⁴M</em>

<em />

Replacing in ksp formula:

4.8x10⁻²⁰= [Cu²⁺] [1.26x10⁻⁴]²

<em>3.0x10⁻¹² = [Cu²⁺] </em>

That means the maximum amount of Cu²⁺ that can be in solution is 3.0x10⁻¹²M, thus, molar solubility of Cu(OH)₂ is

<em>E) 3.0x10⁻¹²</em>

3 0
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