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Feliz [49]
2 years ago
10

What volume of hydrogen ( in L ) is produced from the complete reaction of 56.49 g of magnesium metal at STP

Chemistry
1 answer:
alexandr1967 [171]2 years ago
6 0

Answer:

<em>Mg = 24.30 g/mol) Mg(s) + 2HCl(aq) MgCl2(aq) + H2(g) Hint: 1 mole of gas at STP occupies 22.4 L</em>

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A saline solution with a mass of 400 g has 30 g of NaCl dissolved in it. What is the mass/mass percent concentration of the solu
maria [59]
(g solute/g solution)*100 = % mass/mass

30 g / 400 * 100 

0,075 * 100

= 7,5% w/w

hope this helps!

3 0
3 years ago
Calculate the molar concentration of the Cl⁻ ions in 0.92 M MnCl2(aq).
scZoUnD [109]
MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
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6 0
3 years ago
Read 2 more answers
What is the electron configuration of an electrically neutral alkaline earth metal? please explain​
vlabodo [156]

Answer:

The elements in Group 2 (beryllium, magnesium, calcium, strontium, barium, and radium) are called the alkaline earth metals (see Figure below). These elements have two valence electrons, both of which reside in the outermost s sublevel. The general electron configuration of all alkaline earth metals is ns

8 0
3 years ago
2 moles of sodium phosphate reacts with 3 moles of
miss Akunina [59]

Answer: 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of  calcium chloride

Explanation:

The balanced chemical equation is:

2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2  

According to stoichiometry :

2 moles of Na_3PO_4 require 3 moles of CaCl_2

Thus both are limiting reagent as both will limit the formation of product.

As 2 moles of Na_3PO_4 reacts with 3 moles of CaCl_2 give = 6 moles of NaCl

Thus 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of  calcium chloride

 

4 0
3 years ago
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