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Serjik [45]
3 years ago
7

Suppose you want to use a confidence interval to estimate the true mean number of calories found in candy bars. It is known that

the distribution of the calories is normal. How many candy bars must you have in order to be sure the sampling distribution of x is normal?

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

See explanation

Step-by-step explanation:

Solution:-

- To estimate the true mean number of calories found in candy bars we need a confidence interval for the distribution.

- Assuming population is normally distributed. We take a sample of "n" number of candies from the population. It is given that the sample conforms to the condition of normality irrespective of the sample size "n"

- If the population is not normally distributed then to approximate the sample for normality then the sample size must be large enough for it to be covered throughout 3 standard deviations.

- It is found through empirical results that "sufficient large" sample size of n:

                                        n ≥ 30

- Complies with the conditions of normality.

svetlana [45]3 years ago
5 0

Answer:

See explaination.

Step-by-step explanation:

Sampling distribution can be defined as a probability distribution of a statistic which is gotten through a large number of samples usually drawn from a specific population.

The sampling distribution of a given population can be described as the distribution of frequencies of a range of different outcomes that could possibly occur for a statistic of a population.

Please refer to attachment for a step by step technique to prove How many candy bars must you have in order to be sure the sampling distribution of x is normal.

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xxMikexx [17]
Ok I know how to do this but what do I need to do?
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3 years ago
What is the answer to 4/5+9/11
SCORPION-xisa [38]
Hi there! 
When adding fractions we ALWAYS need to make sure the that denominators are the SAME .We need to find a common denominator so that the two fractions are on the same terms. In the end, the denominator stays the same. Let's start: 
We are given 2 fractions to add: 
\frac{4}{5} + \frac{9}{11}

We need to find a LEAST common denominator, start by listing the factors of 5 and 11 since both of these numbers are in the denominator. 

Factors of 5: <span>5, 10, 15, 20, 25, 30, 35, 40, 45, 50, </span><span>55
Factors of 11: </span><span>11, 22, 33, 44, </span><span><span>55

</span>As we see above, 55 is our LCD (least common denominator) 

We can change the denominator of both fractions to 55 since this is our LCD:
</span>\frac{4}{55} + \frac{9}{55}

However, if the denominator changes, the numerator changes as well. We use the following formula to find the numerators: 

(Common Denominator ÷ Denominator) x Numerator =  Numerator

Lets start by finding the numerator for the first fraction: 
4/55

<span>(55 (common denominator) ÷ 5 (original denominator) × 4 (numerator) = 44</span>

The first fraction becomes: 

\frac{44}{55}

Now let's do the second:

9/55

<span>(55(common denominator) ÷ 11(original denominator))×9(</span>numerator) = 45

Now we have: 

\frac{45}{55}

Now we have two fractions to add: 

\frac{44}{55} + \frac{45}{55}

Only add the numerators, the denominators stay the SAME !

44+45=89

Final answer: \frac{89}{55}

If you have further questions on this problem, please do not hesitate to comment below! :) Have a nice day! 

7 0
2 years ago
1, I cannot fail this if I do I have a F in math!! Please make sure u know it’s correct I can’t do it alone.
Anton [14]

Answer:One way of knowing the correct answers, we substitute the ordered pairs to the function and see whether it would make the function true.

3x – 4y = 21

A. (−3, 3)

3(-3) – 4(3) = 21

-21 = 21 ---------------> not equal

B. (−1, −6)

3(-1) – 4(-6) = 21

21 = 21 ---------------> equal

C. (7, 0)

3(7) – 4(0) = 21

21 = 21 ---------------> equal

D. (11, 3)

3(11) – 4(3) = 21

21 = 21 ---------------> equal

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Maria ran 4 7/8 miles on monday she ran 2 3/8 miles on friday, how many miles did maria run altogether?
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4 7/8  + 2 3/8 =

= 39/8 + 19/8

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