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lapo4ka [179]
3 years ago
9

Which compound does H2SO4 represent when in an aqueous solution?

Chemistry
2 answers:
solong [7]3 years ago
4 0
H₂SO₄ represents Sulphuric acid or SO₄²⁻ ion when in aqueous as well as H⁺ and a little amount of HSO₄⁻ all of these ions can form in aqueous on dissolving H₂SO₄
nexus9112 [7]3 years ago
3 0

Answer:The correct answer is option b.

Explanation:

Acid a are those compound which gives hydronium ions in their aqueous solution.

HA+H_2O\rightarrow A^-+H_3O^+

H_2SO_4+H_2O\rightarrow SO_{4}^{2-}+2H^+

Sulfuric acid in its aqueous solution gives  sulfate ions and hydronium ions.

Hence, the correct answer is option b.

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Les étapes nous permettant de sentir une tarte aux pommes
Dmitry [639]

Answer:

L'ordre correct est le suivant;

1. Les cils olfactifs capturent les molécules chimiques odorantes

2. Le signal des molécules chimiques est transformé en impulsions nerveuses

3. L'influx nerveux est transféré au cerveau par le nerf olfactif au bulbe olfactif du cerveau antérieur

4. Les odeurs sont perçues

Explanation:

Pour sentir la pomme, l'air autour de la pomme est inhalé rapidement pour aider les produits chimiques odorants à entrer dans la cavité nasale.

La cavité nasale a des cellules spéciales qui sont réceptives aux produits chimiques odorants, qui envoient un message au cerveau lors de la liaison au produit chimique par le nerf olfactif. Lorsque le message arrive au bulbe olfactif du cerveau antérieur, il est analysé et l'odeur est identifiée et / ou reconnue.

Par conséquent, l'ordre correct est le suivant;

1. 1. Les cils olfactifs captent les molécules chimiques odorantes

2. 2. Le signal des molécules chimiques est transformé en impulsions nerveuses

3. 4. L'influx nerveux est transféré au cerveau par le nerf olfactif au bulbe olfactif du cerveau antérieur

4. 3. Les odeurs sont perçues.

3 0
3 years ago
If a hydrogen atom has its electron in the n = 3 state, how much energy in ev is needed to ionize it?
tensa zangetsu [6.8K]

The energy of the hydrogen atom will be -0.85 ev.

Ionization, also known as ionization, would be the phenomenon by which an atom or molecule gains or loses electrons to acquire a negative and positive charge, frequently in conjunction with those other chemical changes. Ions are the name for the electrically charged molecular or atom that results.

These chemicals are known as ionic compounds, with table salt serving as an example. Ionization would be the process of removing electrons from such an element as well as a molecule as well as the dissociation of an ionic material, such as salt, itself into the individual ions in a solution like water.

The energy of hydrogen atom will be calculated by using the formula:

E_{n} = -13.6 ev / n^{2}

where, E_{n} = energy of nth level, n is the state.

It is given that, n = 3 .

Now put the value of n in above equation.

E_{4} = -13.6 ev / 4^{2}\\E_{4} = -13.6 ev  / 16\\E_{4} = -0.85 ev

Therefore, the energy of the hydrogen atom will be -0.85 ev.

To know more about energy

brainly.com/question/1932868

#SPJ4

4 0
2 years ago
Use the drop-down menus to select the correct name for each of the organic compounds.
Molodets [167]

Answer:

Here's what I get  

Explanation:

CH₃CH₂CH₂CH₂CH₂CH₃ —  hexane

CH₂=CHCH₂CH₂CH₂CH₃ —  hex-1-ene is the preferred IUPAC name (PIN). 1-Hexene is accepted

CH₃C≡CCH₃ —  but-2-yne (PIN); 2-butyne is accepted

CH₃CH(CH₃)CH₂CH₂CH₃ — 2-methylpentane

CH₃CH₂CHCICH₂CH₃ — 3-chloropentane

5 0
4 years ago
Read 2 more answers
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
How many bromine atoms are present in 39.4 g of CH2Br2
strojnjashka [21]
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
7 0
4 years ago
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