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Vaselesa [24]
3 years ago
15

A scientist monitors the contents of five duck nests in parks, five duck nests in zoos, and five duck nests in the wild during t

he spring and summer for three years. He makes a multiple line graph to plot and compare data for the three locations. Which question describes what the scientist is most likely testing?
Chemistry
1 answer:
zlopas [31]3 years ago
8 0
He is probably studying the behavioral patterns of ducks in different environments.
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What is the defintion of speed of light
Vika [28.1K]

Answer:

a fundamental universal constant, the speed at which light and all forms of electromagnetic radiation travel in a vacuum, standardized ...

Explanation:

299 792 458 m / s

3 0
3 years ago
5. Any push or pull acting on an object is called a ?
slamgirl [31]

Answer:

C. force

Explanation:

8 0
3 years ago
when 4.00 g of sulfur are combined with 4.00 g of oxygen, 8.00 g of sulfur dioxide (so2) are formed. what mass of oxygen would b
Darina [25.2K]

Answer:

6g O2

Explanation:

Mole to mole ratio:

A balanced chemical equation shows a chemical reaction while maintaining the law of conservation of mass. The coefficients of the substances are known to be very helpful in computations as they represent the equivalent amounts of moles of the species that would be participating in the reaction.

We set up the chemical equation and then find the balanced chemical expression.

S+O2→SO3

Balance 

2S+3O2→2SO3

We use the following values for the variables:

mS=4.0 gm

We proceed with the solution.

mO2= 4 g S × 1 mol S/ 32 g S × 3 mol O2/ 2 mol S × 32g O/ 1 mol O2

mO2 = 6 g

learn

brainly.com/question/17961582?referrer=searchResults

7 0
1 year ago
131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___
inn [45]
For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,         
8.04 days    = ln 2 / λ                         
λ   = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at  t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ   = ln 2 / 8.04 days = 0.693 / 8.04 days
t    = 13.0 days 

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0
2 years ago
When aqueous solutions of potassium cyanide and hydrobromic acid are mixed, an aqueous solution of potassium bromide and hydrocy
mrs_skeptik [129]

Answer:

hey there

Explanation:

CN- (aq) + H+ (aq) → HCN(I)

The reactants are aqueous solutions:

NaCN(aq) and HBr(aq)

When you mix these compounds you make pure HCN (I)

The molecular equation is:

NaCN(aq) + HBr(aq) → NaBr(aq) + HCN(I)

When you dissociate the reactants, you have: Nat(aq) +CN¯(aq) + H*(aq) + Br−(aq) → Nat(aq) + ->

Br (aq) + HCN(I)

Sodium bromide, it is a salt, that can also be

dissociated in the solution

To make, the net ionic equation you remove the repeated ions

CN- (aq) + H+ (aq) → HCN(I)

If you like my answer please mark as brainliest

8 0
2 years ago
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