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DENIUS [597]
4 years ago
10

7. In which quadrant does the solution of the system fall?

Mathematics
1 answer:
tia_tia [17]4 years ago
6 0
From X + Y = 4 
<span>Y = 4 - X </span>
<span>Substituite this for Y in 2X - Y = 2 to get </span>
<span>2X -(4 - X ) = 2 </span>
<span>2X -4 +X = 2 </span>
<span>3X = 6 </span>
<span>X = 2 </span>
<span>Now return to X + Y = 4 </span>
<span>Knowing X = 2, </span>
<span>2 + Y = 4 </span>
<span>Y = 4 - 2 </span>
<span>Y = 2 </span>
<span>The solution is (X,Y) = (2,2) </span>
<span>This is quadrant I </span>
<span>Answer is A</span>
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Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

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4 years ago
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Answer:

$1900.80

Step-by-step explanation:

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The simple interest accumulated

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Answer:

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3 years ago
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