Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
Answer:
B: Bind
Explanation:
JavaFX property binding permits the synchronization of the value of two properties in such a way that whenever there is a change in one of the properties, there is an immediate update on the value of the other property. In this way, The StringProperty method bind receives an ObservableValue as an argument. When the ObservableValue changes, the bound property is updated accordingly.
To get the number ot decoder output:
2^n; where n is number of input
2^4
2 × 2 × 2 × 2 = 16 outputs
Answer:
Write a C program to check whether a number is even or odd using if else. How to check whether a number is even or odd using if else in C program. C Program to input a number from user and check whether the given number is even or odd. Logic to check even and odd number using if...else in C programming.
Explanation:
