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igor_vitrenko [27]
4 years ago
5

A 22kg box slides down a 30.0 degree incline. If there is no friction, what is the acceleration of the box?

Physics
1 answer:
Rashid [163]4 years ago
6 0

Answer:

Acceleration of the box is 4.9 m/s².

Explanation:

The free body diagram is shown below.

The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to mg\sin \theta acting along the incline.

Therefore, as per Newton's second law of motion,

Net force = mass\times acceleration

Now, net force acting along the incline is only mg\sin \theta

Therefore,

mg\sin \theta=ma\\a=g\sin \theta

Now, g=9.8\textrm{ and } \theta = 30

Therefore, the acceleration of the box is given as:

a=9.8\times \sin(30)=9.8\times 0.5=4.9\textrm{ }m/s^{2}

Acceleration of the box is 4.9 m/s².

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The vector perpendicular to this direction, as perhaps a suspension motion over a bump, would be described as vertical even if it is not strictly vertical.

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