F(of spring)=230x=ma=3.5(5)=17.5=230x; x=0.07m.
Answer:
115 kPa
Explanation:
Use Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
Assuming no elevation change, h₁ = h₂.
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
Plugging in values:
(582,000 Pa) + ½ (1000 kg/m³) (1.28 m/s)² = P + ½ (1000 kg/m³) (30.6 m/s)²
P = 115,000 Pa
P = 115 kPa
Answer:
1 / 2 m v^2 = L m g (1 - cos θ)
This is the KE due to the pendulum falling from a 25 deg displacement
v^2 = 2 L g (1 - cos 25) = 2 * 2 * 9.8 (1 - .906) = 3.67 m^2/s^2
v = 1.92 m/s this is the speed due to an initial displacement of 25 deg
Its speed at the bottom would then be
1.92 + 1.2 = 3.12 m/s since it gains 1.92 m/s from its initial displacement
Answer: something must drop it over
Explanation:
