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Setler [38]
2 years ago
7

What do we call factors that control traits

Physics
1 answer:
True [87]2 years ago
8 0
The factors that control traits are the alleles. They are determined by two chromosomes which is obtained from the parents. For instance, you are able to roll your tongue, you have two chromosomes one for being able to roll and the other for not being able but since you have that ability you get the allele of being able to roll out your tongue.
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HELP PLSSSSSSS ASPA 20 pointsssss
FrozenT [24]

Answer:

Hey guess what there's no question genius

Explanation:

8 0
3 years ago
Read 2 more answers
A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input
KATRIN_1 [288]

Answer:

The peak-to-peak ripple voltage = 2V

Explanation:

120V and 60 Hz is the input of an unfiltered full-wave rectifier

Peak value of  output voltage = 15V

load connected = 1.0kV

dc output voltage = 14V

dc value of the output voltage of capacitor-input filter

where

V(dc value of output voltage) represent V₀

V(peak value of output voltage) represent V₁

V₀ = 1 - ( \frac{1}{2fRC})V₁

make C the subject of formula

V₀/V₁ = 1 - (1 / 2fRC)

1 / 2fRC = 1 - (v₀/V₁)

C = 2fR ((1 - (v₀/V₁))⁻¹

Substitute  for,

f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V

C = 2 * 240 * 1 (( 1 - (14/15))⁻¹

C = 62.2μf

The peak-to-peak ripple voltage

= (1 / fRC)V₁

= 1 /  ( (120 * 1 * 62.2) )15V

= 2V

The peak-to-peak ripple voltage = 2V

3 0
3 years ago
If a person climbed Mt. Everest has a mass of 105 kg and a weight of 625 N what would be the acceleration due to gravity?
DanielleElmas [232]

The acceleration due to gravity would be 5.95 m/s²

A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.

  • Force = mass × acceleration.

From the parameters given:

  • Mass = 105 kg
  • Force = 625 N

By replacing the given values into the above equation, we can determine the acceleration.

∴

625 N = 105 kg × acceleration.

\mathbf{acceleration = \dfrac{625 \ N}{105 \ kg}}

acceleration = 5.95 N/kg

  • Since 1 N/kg = 1 m/²

acceleration = 5.95 m/s²

Learn more about acceleration(a) here:

brainly.com/question/14344386

3 0
2 years ago
If a crane worker lifts a crate with a mass of 250 kg from the ground to a
mina [271]

D.

The gravitational of a body is possessed by the body due to the virtue of its position.

The formula for gravitational potential energy is,

                                P.E = mgh joules

Substituting the values

196*9.8*250= 49k

7 0
2 years ago
A 23.7 kg kid slides down a
anyanavicka [17]

Answer:

\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}

Explanation:

Mass of the kid 23.7 kg.

\text { The kid is accelerating down at an angle is } 47.2^{\circ} .

^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

a=\frac{170.24}{23.7}

a=7.18 \mathrm{m} / \mathrm{s}^{2}

\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}

6 0
3 years ago
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