The answer is 167 pounds.
Answer:
the mass of the cart is 150 kg
Explanation:
given,
mass of boy(m) = 50 kg
speed of boy (v)= 10 m/s
initial velocity of cart (u) = 0
final velocity of cart(V) = 2.5 m/s
mass of the cart(M) = ?
m v + M u = (m + M ) V......................(1)
50× 10 + 0 = (50 + M ) 2.5
M =
M = 150 Kg
hence, the mass of the cart is 150 kg
Answer:
the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
Explanation:
Given that;
speed of car V = 120 km/h = 33.3333 m/s
Reaction time of an alert driver = 0.8 sec
Reaction time of an alert driver = 3 sec
extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec
now, extra distance that car will travel in case of sleepy driver will be'
S_d = V × 2.2 sec
S_d = 33.3333 m/s × 2.2 sec
S_d = 73.3333 m
hence, number of car of additional car length n will be;
n = S_n / car length
n = 73.3333 m / 5m
n = 14.666 ≈ 15
Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
Answer:
250Nm
Explanation:
Given parameters:
Length of the long pry bar = 1m
Force acting on it = 250N
Angle = 90°
Unknown:
Amount of torque applied = ?
Solution:
Torque is the turning force on a body that causes the rotation of the body.
The formula is given as:
Torque = Force x r Sin Ф
r is the distance
So;
Torque = 250 x 1 x sin 90 = 250Nm
v = final velocity
u = initial velocity
t = time taken
the acceleration of the cyclist is
approximately 3.33 m/s^2
the acceleration of the car is
5.0 m/s^2
