Answer:
The smaller number is 127
Step-by-step explanation:
Lets write the given problem in equation form
sum of consecutive numbers n and n + 1 = n + n + 1 = 2n + 1
now we find twice of the sum of consecutive numbers n and n + 1
2*(2n + 1) = 4n + 2
given that
twice the sum of consecutive numbers n and n + 1 is 510
thus,
4n + 2 = 510
=> 4n = 510 -2 = 508
=> n = 508/4 = 127
Thus, the numbers are n = 127
n+1 = 127 + 1 = 128
the smaller number is 127
Answer:
Step-by-step explanation:
y÷2+x
2÷2+1
1+1
2
Answer: x^2 - 14x + 49
Explanation:
1) Divide the coefficient of x by 2:
14 / 2 = 7
2) so you have to add 7^2 = 49
x^2 - 14x + 49
3) that trinomial is equivalent to:
=> (x - 7)^2
4) prove that using the formula (a - b)^2 = a^2 - 2ab + b^2
(x - 7)^2 = x^2 - 14x + 49
Then you have to add 49 to complete the square. and form a perfect square trinomial.
Answer:
Step-by-step explanation:
First both the rational numbers should have same denominators. So, find least common denominator
Least common denominator is 10

Now multiply the numerator and denominators of the both the numbers by 10.

Answer:
=
+
+
Step-by-step explanation:
=multiple ways to climb a tower
When n = 1,
tower= 1 cm
= 1
When n = 2,
tower =2 cm
= 2
When n = 3,
tower = 3 cm
it can be build if we use three 1 cm blocks
= 3
When n = 4,
tower= 4 cm
it can be build if we use four 1 cm blocks
= 6
When n > 5
tower height > 4 cm
so we can use 1 cm, 2 cm and 4 cm blocks
so in that case if our last move is 1 cm block then
will be
n —1 cm
if our last move is 2 cm block then
will be
n —2 cm
if our last move is 4 cm block then
will be
n —4 cm
=
+
+