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Marina86 [1]
4 years ago
15

11 POINTS PLZ HELP EMERGENCY

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

Part A

The given expression is:

(-5(1+2i)+3i(3-4i)

We expand to get:

-5-10i+9i-12i^2

Note that i^2=-1

12-5-10i+9i

-5-10i+9i+12

7-i

Part Bi)

The given expression is;

\sqrt{-50}

We simplify to get:

\sqrt{25\times 2\times -1}

\sqrt{25\times} \sqr{2}\times \sqrt{-1}

Note that:

\sqrt{-1}=i

5\sqr{2}i

This is now of the form a+bi, where a=0,b=5\sqr{2}.

This explains why it is a complex number;

Part bii)

The given expression is :

\frac{\sqrt{-50} }{\sqrt{5}}

We simplify to get

\sqrt{\frac{-50 }{5}}

\sqrt{-25}

\sqrt{-25}=\sqrt{25}\times \sqrt{-1}

\sqrt{-25}=5\times i

\sqrt{-25}=5i

Part C

We want to simplify:

i^{22}

We rewrite in terms of i^2

i^{22}=(i^2)^{11}

i^{22}=(-1)^{11}

i^{22}=-11

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6. Richy has a bag of marbles. He gave 5/12 of
Tems11 [23]

Answer:

7/12

Step-by-step explanation:

12/12-5/12=7/12

7 0
3 years ago
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

3 0
3 years ago
6. a. Name a pair of equations that have exactly one point of intersection. How do you know?
True [87]

Answer:

A system of linear equations will have exactly one point of intersection, for example:

2x+y=5

-x+y=2

However, a system of linear equations with no solution will have no points of intersection, for example:

-4x+10y=6

2x-5y=3

Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe

And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)

I attached a photo below, and one of how to graph it

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
The candle factory made 498 red candles and 204 white candles each day. About how many candles did the factory make in a day alt
stiv31 [10]

Answer:

about 700

Step-by-step explanation:

you add 204 + 498=

4 0
3 years ago
Read 2 more answers
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