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Marina86 [1]
4 years ago
15

11 POINTS PLZ HELP EMERGENCY

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

Part A

The given expression is:

(-5(1+2i)+3i(3-4i)

We expand to get:

-5-10i+9i-12i^2

Note that i^2=-1

12-5-10i+9i

-5-10i+9i+12

7-i

Part Bi)

The given expression is;

\sqrt{-50}

We simplify to get:

\sqrt{25\times 2\times -1}

\sqrt{25\times} \sqr{2}\times \sqrt{-1}

Note that:

\sqrt{-1}=i

5\sqr{2}i

This is now of the form a+bi, where a=0,b=5\sqr{2}.

This explains why it is a complex number;

Part bii)

The given expression is :

\frac{\sqrt{-50} }{\sqrt{5}}

We simplify to get

\sqrt{\frac{-50 }{5}}

\sqrt{-25}

\sqrt{-25}=\sqrt{25}\times \sqrt{-1}

\sqrt{-25}=5\times i

\sqrt{-25}=5i

Part C

We want to simplify:

i^{22}

We rewrite in terms of i^2

i^{22}=(i^2)^{11}

i^{22}=(-1)^{11}

i^{22}=-11

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Del dinero que tenia gaste 1/3 en comida y 1/8 en pasaje, quedándome aún 39 pesos ¿Cuanto tenia al principio?
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Explicación paso a paso:

Dado que:

Sea la cantidad total poseída = t

Fracción gastada en alimentos = 1/3 t = t / 3

Fracción gastada en pasaje = 1/8 t = t / 8

Monto restante después del gasto total = 39 pesos

Fracción total gastada:

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= (8t + 3t) / 24

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