True or False Decreasing the temperature and movement of particles will speed up the reaction rate.

Kendra conducts an experiment. She mixes two chemicals, resulting in a chemical reaction. Based on Kendra's

kondaur [170]

Answer: It changed in identity and properties.

Explanation:

3 0

3 years ago

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

balu736 [363]

Answer:

Cost to supply enough vanillin is $3.2\$$

Explanation:

Threshold limit of vanillin in air is $2.0\times 10^{-11}g$ per litre means there should be $2.0\times 10^{-11}g$ of vanillin in 1L of air to detect aroma of vanillin.

$1ft^{3}=28.32L$

So, $5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L$

So amount of vanillin should be present to detect = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$

As cost of 50 g vanillin is $112\$$ therefore cost of $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$ vanillin = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$$

5 0

3 years ago

In which of the pairs listed below are both compounds strong electrolytes? Are any strong acids or bases?

Ganezh [65]

<h3>Answer:</h3>

NaCl and Sr(OH)2

<h3>Explanation:</h3>

An electrolyte is a substance that is either in molten or aqueous form that can be decomposed by passing an electric current through it.
Electrolytes are classified as either strong electrolytes or weak electrolytes.
Strong electrolytes are either strong bases or acids which completely ionizes to give mobile ions which are responsible for conduction of electricity.
NaCl is a salt and Sr(OH)₂ is a strong base, both are strong electrolytes.

5 0

3 years ago

The solubility of potassium chloride is 34 g KCl

kenny6666 [7]

Answer: When 20 grams of potassium chlorate, KClO3, is dissolved in 100 grams of water at 80 ºC, the solution can be correctly described as:, unsaturated

At approximately what temperature does the solubility of sodium chloride, NaCl, match the solubility of potassium dichromate, K2Cr2O7?, 60 ºC

Explanation:

8 0

3 years ago

How would you prepare 1.00 L of a 0.400M solution of copper(II)sulfate, CuSO4?

Ber [7]

We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of $CuSO_4$ we have to dilute??

It's simple.

$\eta=\frac{m}{MM}$

Using a periodic table we can find the molar mass of $Cu,~~S~~and~~O$

$MM_{CuSO_4}=153.9~g/mol$

Then

$m=\eta*MM$

now we can replace it

$m=0.400*159.6$

$\boxed{\boxed{m=63.84~g}}$

Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M

3 0

3 years ago

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