The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 1.25 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of stomach acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl neutralized is 1.25 mL
Answer:
15 atoms
increases
Explanation:
10 hydrogen atoms + 5 oxygen atoms = 15 atoms
6.32 KJ is how much heat is given off
Answer:
2.355atm
Explanation:
To get the pressure of helium, we need to get the mole fraction of helium.
The total mole fraction for any mixture of gases equals 1. Hence to get the mole fraction of the helium, we simply subtract the addition of the mole fractions of neon and argon from 1.
This means - 1 - 0.47 - 0.23 = 0.3
Now, to get the pressure of the helium gas, we simply multiply the total pressure by 0.3. This is 0.3 * 7.85 = 2.355 atm
