Question

2Na + Cl2 → 2NaCI How many grams of NaCl will be produced from 33.0 g of Na and 34.0 g of Cl.?

Answer 1

54.936 grams of NaCl will be produced from 33.0 g of Na and 34.0 g of Cl.

Explanation:

Data given:

mass of Na = 33 grams

mass of $Cl_{2}$ = 24 grams

atomic mass of Na = 23 grams/moles

atomic mass of Cl = 70 grams/mole

mass of NaCl formed =?

atomic mass of NaCl = 58.44 gram/mole

balanced chemical reaction:

2Na + $Cl_{2}$ ⇒ 2NaCl

number of moles = $\frac{mass}{atomic mass}$

putting the values in the equation:

number of moles of Na = $\frac{23}{33}$

                                     = 0.69 moles

number of moles of chlorine gas = $\frac{34}{71}$

                                                        = 0.47 moles

limiting reagent is chlorine gas in the reaction

from the balanced chemical reaction:

1 mole of chlorine gas reacts to form 2 moles of NaCl

then 0.47 moles of chlorine gas will form x moles

$\frac{2}{1}$ = $\frac{x}{0.47}$

x = 0.94 moles of NaCl is formed.

mass = atomic mass x number of moles

mass = 58.44 x 0.94

         = 54.936 grams of NaCl is produced.