The answer is 120.
Needs full space
We know that
in the triangle TQS
<span>applying the Pythagorean theorem
QS</span>²=TS²+TQ²---------> TQ²=QS²-TS²--------> TQ²=18²-9x²-----> equation 1
in the triangle TRS
TS²=TR²+RS²--------------> TR²=TS²-RS²-------> TR²=9x²-144----> equation 2
in the triangle QTR
TQ²=TR²+36-----------> equation 3
<span>I substitute 1 and 2 in 3
</span>18²-9x²=9x²-144+36--------> 18x²-432=0------> x²=24-------> x=√24
x=2√6
TS=3*x------> 3*2√6-----> 6√6
TS=6√6 units
the answer is
TS=6√6 units
<span>6 is the square root of 6 units</span>
Take out the factor of 3 from both numbers
(69)/3 = 23
(12)/3 = 4
69 + 12 can be rewritten as 3(23 + 4)
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The area of rectangle with length l and width w is
If the length of rectangle is expressed as 
and the width of rectangle is expressed as 
, then the area of rectangle is
