"6 pencils and 5 pens together cost ₹ 56". express this situation as linear equation in two variables
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The Lego is submerged under the oil and therefore, is more dense than the oil
The possible density of the oil is the option;
<u>0.79 g/cm³</u>
Reason:
Given:
The density of Lego = 0.85 g/cm³
Density of oil = Required
Solution:
The density of an object is the mass per unit volume it occupies
Increase in density increases the mass a unit volume occupies, therefore, a
more dense object is heavier than a less dense object such that the less
dense object will float on a dense object
The oil is floating on the Lego, therefore, the Lego is more dense than the
oil, and we have;
- Density of Lego > Density of oil
The density of Lego = 0.85 g/cm³
Therefore;
0.85 g/cm³ > Density of oil
From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³
Therefore, the possible density of the oil is <u>0.79 g/cm³</u>
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