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mamaluj [8]
3 years ago
11

3 units

Mathematics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

\large\boxed{BC=\sqrt{13}}

Step-by-step explanation:

\text{If}\ a\leq b\leq c\ \text{are lengths of sides of a right triangle, then}\\\\a^2+b^2=c^2.\\\\\text{We have:}\ 2

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Step-by-step explanation:

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There are 527 pencils,646 erasers,748 sharpeners . these are to be put in separate packets containing the same no. of items. fin
Ksju [112]

To \; find \; the \; maximum \; number \; of \; items \; possible \; in each \; packet,\\we \; need \; to \; find \; the \; Greatest \; Common \; Factor\\ \; of \; 527 \; Pencils, \; 646 \; erasers \; and \; 748 \; sharpeners.\\\\We \; need \; to \; list \; the \; Factors \; of \; each \; number \; as \; given \; below\\ \; and \; identify \; the \; greatest \; common \; factor.

The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.

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* Required
Furkat [3]
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