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andrey2020 [161]
3 years ago
6

What is the reciprocal of?

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
4 0

Answer:

8

Step-by-step explanation:

Just flip it up... it will be 8

kupik [55]3 years ago
4 0

Answer:

0.125

When you multiply fractions, multiply numerators to find solution numerator, then multiply denominators to find solution of denominator. Divide your fractions, multiply the first fraction by reciprocal of the second fraction. It can be crossed multiplied.

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How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
Evaluate the expression:<br> 9 +7(5-2)<br> Using PEDMAS<br><br> yall i suck at math
ANEK [815]

Hello! :)

Let's use PEMDAS.

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

(5-2) = 3 Do parenthesis.

7 × 3 = 21 Multiply with what we got after doing the parenthesis.

9 + 21 = 30 Add with what we had left.

30

Hope this helps!

ELITEDIPER

5 0
4 years ago
Need help on 7,8,9,10,11 and 12 DUE TOMORROW
Dennis_Churaev [7]
7) (12 + 6)/(2 +4)
(18)/(6) = 3

8) (42 - 24)/6
(18)/6 = 3

9) (9 + 16) - (2 x 4)
25 - 8 = 17

10) 60 - (3 + 2) x 5
60 - 5 x 5
60 - 25 = 35

11) 18 + (9/3) 
18 + 3 = 21

12) 5 x (2 + 4 + 3)
5 x (9) = 45



hope this helps
3 0
3 years ago
Read 2 more answers
Need help asap pls :)
pogonyaev

Answer:

See explanation below.

Step-by-step explanation:

First I'm going to find angle 2. Angle two plus 55 is equal to 115. 180-115=65. 65-55=10 Angle 2 = 10

Next, we can find angle 3. 55+10=65. 180-65=115. Angle 3 = 115

Angle 2 is equal to angle 5, angle 3 is equal to angle 6, and angle 4 is equal to 55.

Angle 5 = 10

Angle 4 = 55

Angle 6 = 115

Now we can find angle 8. 180-115=65. Angle 8 = 65

Angle 11 = 65

Angle 12 = 115

10+115=125 Angle 10 = 125

180-125 = 55 Angle 9 = 55

Angle 14 = 55

Angle 13 = 125

7 0
3 years ago
Read 2 more answers
In order to circumscribe a circle on a triangle, which line must you construct?
SIZIF [17.4K]
<span>D) perpendicular bisector <em>I believe.
</em></span>
6 0
3 years ago
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