The permutation shows that when one has been cast yet, the different ways that are there to cast Fantine from the 28 women is 28.
<h3>How to calculate the value?</h3>
The different ways that are there to cast Fantine from the 28 women will be:
= 28!/(28 - 1)!
= 28!/27!
= 28
When Fantine has already been cast, the number of ways that are there to cast adult Cosette from the remaining women will be:
= 27!(27 - 1)!
= 27!/26!
= 26
When Fantine and adult Cosette have already been cast, the different ways that are there to cast Éponine from the remaining women is:
= (28 - 2)!/(28 - 2 - 1)!
= 26!/25!
= 25
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I can't factor that.
Is the equation input correctly?
Try them and see.
For the first:
3(-3) + 0 = -9 . . . . not > -8
3(-2) + (-1) = -7 . . . is > -8 . . . . . 2) (-2, -1) is a solution
For the second:
4 - 4(-2) = 12 . . . . not ≤ -6
-2 -4(1) = -6 . . . . . is ≤ -6 . . . . . . 2. (1, -2) is a solution
Answer:
Consider matrix A.
What is the inverse of A? Fill in the missing elements in the matrixs.
Step-by-step explanation:
Consider matrix A.
What is the inverse of A? Fill in the missing elements in the matrixs.