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3 years ago

Ionic compounds have high melting points because a lot of energy is needed to break the bonds between the ions.

Physics

2 answers:

velikii [3]3 years ago

5 0

Its true the ionic compounds have a higher melting point

leva [86]3 years ago

5 0

Answer:

True

Explanation:

The ionic compounds have a high melting point because the ionic bond consists in the donation of the electrons from the metallic ion to the non-metallic ion due to the difference in electronegativity. Because of this, the ion core of the elements of this compounds are very close to each other, having a strong bond between all the speciements, therefore elevating the melting point.

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Two forces one of 12N and another of 5N act on abody in such away that they makes an angel of 90 with each other, what is the re

Murljashka [212]

Answer:

13 N

Explanation:

From the question,

If two forces act at right angle to each other, Their result force can be calculated using Pythagoras theorem.

R'² = R₁²+R₂²....................... Equation 1

Where R' = Resultant force, R₁ = First force, R₂ = Second force.

Given: R₁ = 12 N, R₂ = 5 N

Substitute these values into equation 1

R'² = 12²+5²

R'² = 144+25

R'² = 169

R' = $\sqrt{169}$

R' = 13 N.

Hence the resultant force is 13 N

6 0

3 years ago

4. For a point charge, we derived an expression from Gauss’s law for the electric field a distance r away. You have a point char

IrinaVladis [17]

Answer:

Explanation:

A point charge of +2q centered in a conductive spherical shell of inner diameter a and outer diameter b will induce - 2q charge on the inner surface and +2q charge on the outer surface of the shell. Since 8q charge has been added to the shell , this charge will reside on the outer surface of the shell. so total charge on the outer surface will be 10q. At a point less than a , the electric field will be due to +2q charge situated at the centre . The electric field will be as follows

E = k .2q / r² for r < a

= 8kq/ a²

electric field at a point r = a>b

total charge lying inside is +2q - 2q = 0 . So in the thickness of the shell , electric field will be zero as total charge inside is nil.

For a point at r > b total charge inside is 2q-2q+10q = 10q , so electric field at r which is lying outside the shell .

E = k 10 q / r² for r > b

8 0

3 years ago

What is the chemical equation, for li2+h20-li0h, use the drop down menu?

ASHA 777 [7]

The fact I can get is22

6 0

3 years ago

What can you infer from the fact that metals are good conductors of electricity?

LuckyWell [14K]

Answer:

Knowing that these metals are infact good conductors of electricity we can infer that metals are able to hold and conduct certain temperatures. Another thing we can infer is that these good conductors can be used in connection to transferring energy or electricity.

6 0

3 years ago

Read 2 more answers

An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai

rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion: Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

Vf = Vi + a×t

Vf = 0 + 2.4×3.6

Vf = 2.4×3.6

Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0

3 years ago