Suppose the glass paperweight has index of refraction n=1.38. a) find the value of θ for which the reflection on the vertical su
1 answer:
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A) Both players are moving by uniformly accelerated motion, and we can write the position at time t of each of the two players as follows:
where
is the acceleration of the first player
is the acceleration of the second player
is the initial distance between the two players
and where I put a negative sign in front of the acceleration of the second player, since he's moving in the opposite direction of the first player.
The time t at which the two players collide is the time t at which
, therefore:
from whic we find
b) We can use the equation of
to find how far the first player run in t=8.5 s:
where
and where I put a negative sign in front of the acceleration of the second player, since he's moving in the opposite direction of the first player.
The time t at which the two players collide is the time t at which
from whic we find
b) We can use the equation of
Answer:
Miller Indices are [2, 4, 3]
Solution:
As per the question:
Lattice Constant, C =
Intercepts along the three axes:
Now,
Miller Indices gives the vector representation of the atomic plane orientation in the lattice and are found by taking the reciprocal of the intercepts.
Now, for the Miller Indices along the three axes:
a =
b =
c =
To find the Miller indices, we divide a, b and c by reciprocal of lattice constant 'C' respectively:
a' =
b' =
c' =