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alukav5142 [94]
3 years ago
12

the coefficient of kinetic friction between a couch and the floor is 0.65. if the couch has a mass of 42 kg and you push it with

a force 600 N, what is the net force in the couch as it slides
Physics
1 answer:
Anna [14]3 years ago
4 0

Explanation:

The net force along the horizontal direction is

\sum{F_x} = F_{applied} - f

where f is the frictional force. We can find the frictional force by looking at the vertical forces acting on the couch:

\sum{F_y} = N - mg = 0 \Rightarrow N = mg

From the definition of frictional force,

f = \mu{N} = \mu{mg} = (0.65)(42\:\text{kg})(9.8\:\text{m/s}^2)

\:\:\:\:= 267.5\:\text{N}

Therefore, the net force on the couch is

\sum{F_x} = 600\:\text{N} - 267.5\:\text{kN} = 332.5\:\text{N}

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3 years ago
A parallel-plate capacitor has square plates that are 7.20 cm on each side and 3.40 mm apart. The space between the plates is co
Lilit [14]

Answer:

U = 218 nJ

Explanation:

We are given;

Spacing between the plates; d = 3.4 mm = 3.4 × 10^(-3) m

Voltage across the capacitor; V = 96 V

Dimension of the square plates is 7.2cm x 7.2cm.

So, Area = 7.2 × 7.2 = 51.84 cm² = 51.84 × 10^(-4) m²

Permittivity of free space; ε_o = 8.85 × 10^(-12) C²/N.m²

From relative permeability table;

Dielectric constant of Pyrex; k1 = 5.6

Dielectric constant of polystyrene; k2 = 2.56

Now, formula for capacitance of a capacitor with Dielectric is;

C = kC_o

Where, C_o = ε_o(A/d)

Since there are 2 capacitors, d will now be d/2 = (3.4 × 10^(-3))/2 m = 1.7 × 10^(-3)

Since we have 2 capacitor, thus ;

C1 = k1*ε_o*(A/d)

C1 = (5.6 × 8.85 × 10^(-12) × (51.84 × 10^(-4))/(1.7 × 10^(-3))

C1 = 1.51 × 10^(-10) F

Similarly;

C2 = (2.56 × 8.85 × 10^(-12) × (51.84 × 10^(-4))/(1.7 × 10^(-3))

C2 = 0.691 × 10^(-10) F

For capacitors in series, formula for total capacitance(Cs) is;

1/Cs = (1/C1) + (1/C2)

Simplifying this, we have;

Cs = (C1*C2)/(C1 + C2)

Plugging in the relevant values ;

Cs = (1.51 × 10^(-10)*0.691 × 10^(-10))/((1.51 × 10^(-10)) + (0.691 × 10^(-10)))

Cs = 0.474 × 10^(-10) F

The formula for energy stored in a capacitor with 2 Dielectrics is given as;

U = ½Cs*V²

So,

U = ½ × 0.474 × 10^(-10) × 96²

U = 2.18 × 10^(-7) J = 218 × 10^(-9) = 218 nJ

8 0
3 years ago
A conducting coil of 1850 turns is connected to agalvanometer, and the total resistance of the circuit is 45.0 ohm.The area of e
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Answer:

0.459 Tesla

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Faraday's law:

Emf = -N\frac{\delta\phi}{\delta t}

Φ= NAB

V =   N Δ (BA) /Δt      

the change in BA

was:    BA =  0   because initially B was zero.

V=IR

   IR =   N B A /Δt

   q / Δt ×R   =      N B A / Δt

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3 0
4 years ago
Suppose a 65 kg person stands at the edge of a 6.5 m diameter merry-go-round turntable that is mounted on frictionless bearings
ozzi

Answer:

0.3165\ \text{rad/s}

Explanation:

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d = Diameter of round table = 6.5 m

r = Radius = \dfrac{d}{2}=3.25\ \text{m}

v = Velocity of person running = 3.8 m/s

I_t = Moment of inertia of turntable = 1850\ \text{kg m}^2

Moment of inertia of the system is

I=I_t+mr^2\\\Rightarrow I=1850+65\times 3.25^2\\\Rightarrow I=2536.5625\ \text{kg m}^2

As the angular momentum of the system is conserved we have

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The angular velocity of the turntable is 0.3165\ \text{rad/s}.

3 0
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