Answer:
see below
Step-by-step explanation:
Angle ACE = DCE since they are vertical angles
Angle A = Angle E parallel lines cut by a transversal form congruent alternate interior angles
Angle B = Angle D parallel lines cut by a transversal form congruent alternate interior angles
When all three angles are equal, the triangles are similar.
We can use ratios to find DE
DE CE
------- = ----------
AB AC
DE 8
------- = ----------
12 10
Using cross products
10 DE = 8*12
10 DE = 96
Divide by 10
DE = 9.6
Given:
Area and altitude PS of ∆PQR are ar(∆PQR) = 180cm² and PS = 15.
To find:
The measure of side QR.
Solution:
According to the given information, PS is an altitude of ∆PQR. It means QR is the base of ∆PQR.
We know that, the area of a triangle is
Substituting the given values, we get
Divide both sides by 15.
Therefore, the measure of side QR is 24 cm.
The area of the isosceles trapezoid is 136 cm2
To find the area of the trapezoid, first we need to make an exact triangle to the other side of the trapezoid, just like in the diagram is showing, ( so you will have 2 triangles in the trapezoid, thinks about that the triangle that is on the diagram is reflecting to the other side) then we have a rectangle on the center of the trapezoid, we use the area formula which is would be 8x13=104, then we take the area formula of the triangle and substitute, which would be (1/2)8x4=16, we multiply 16 by 2 to get 32, this would be the area of the two triangles plus the area of the rectangle which is 104 gives a total of 136 cm2
Hope this help!!! :)
Answer:
a.–12 – 18
Step-by-step explanation:
We have to compute the difference (the subtraction) between the new, colder temperature, which is equal to -12 °C, and the original temperature, which is equal to 18 °C, that is:
colder temperature - original temperature
Replacing with data:
-12 °C - 18 °C = -30 °C
Answer:
3.5 m/s
Step-by-step explanation
Remove brackets
d = t^2 + 0.2t + 3.3t + .66
Combine
d = t^2 + 3.5t + .66
The initial velocity is 3.5
