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3 years ago

10

John is building a stage for a school play.The stage is 151/2 feet long and 20 feet wide. Select all options that represents the

area of the stage,in square feet

2 answers:

Sergeeva-Olga [200]3 years ago

5 0

C and E. hope this helps!

julia-pushkina [17]3 years ago

4 0

C and E might be the answers.

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Let U be a universal set with subsets A and B such that n(U)=118, n(A)=57, n(B′)=69, and n(A∩B)=11. Find the following:

Arturiano [62]

$n(B)=n(U)-n(B')=118-69=49\\
n(A\cup B)=n(A)+n(B)-n(A\cap B)=57+49-11=95\\
n((A\cap B)')=n(U)-n(A\cap B)=118-11=107$

4 0

3 years ago

Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

8 0

3 years ago

How may weeks are there in a year?

Zanzabum

Answer:

There are exactly 52.142857142857 weeks in the year 2019. This is equivalent to 52 weeks and 1 extra day, since there are 365 total days in 2019. Most years have 365 days, but a leap year has 366 days. That adds up to 52 weeks (where each week is exactly 7 days) PLUS 1 or 2 additional days.There are 52 complete weeks in a year. The year has 365 days, leaving one extra day. A leap year has 366 days, adding a second extra day. This makes 52 1/7 weeks in a normal year and 52 2/7 weeks in a leap year..

7 0

3 years ago

Read 2 more answers

How would you do number 12 and 15?

Gnesinka [82]

Answer:

$x_1=x_2=-\dfrac{2}{3}$

Step-by-step explanation:

For the quadratic equation $ax^2+bx+c=0$ the discriminant is defined as

$D=b^2-4ac$

and the quadratic formula for the roots gives us two roots:

$x_1=\dfrac{-b-\sqrt{D}}{2a}$

and

$x_2=\dfrac{-b+\sqrt{D}}{2a}$

For the equation $9x^2 +12x+4=0$ use quadratic formula to find roots:

$D=12^2-4\cdot 9\cdot 4=144-144=0$

So,

$x_1=x_2=\dfrac{-12\pm \sqrt{0}}{2\cdot 9}=-\dfrac{12}{18}=-\dfrac{2}{3}$

7 0

3 years ago

Nathan's lawnmower uses 2/3 of a tank of gas to cut three one-acre lawns. How many one-acre lawns can he cut with a full tank of

Semenov [28]

Using the data you have given, it seems he can cut 1 and a half lawns on a third of a tank of gas. Taking this data, and multiplying it by 3, Nathans lawn mower can mow down 4 one-acre lawns, and a lawn that's half an acre. (Your answer is basically 4 lawns)

7 0

3 years ago