The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Hey there!
3^2 + 7 • 2
3^2 = 3 • 3 = 9
9 + 7 • 2
7 • 2 = 14
9 + 14 = 23
Answer: 23 ☑️
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
It is A and B I think hope it helps
Well, they're both divisible by 2 (24 ÷ 2 = 12) (90 ÷ 2 = 45)
