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Scorpion4ik [409]
3 years ago
13

. Scalene triangle SCL with angle bisector CM

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0
32 but make sure it’s emedicpend PAS
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a spinner has 1 yellow, 2 red, 3 blue and 2 green sections. What is the probability of not getting a yellow?
guajiro [1.7K]
Hello,

spinner has 1 yellow, 2 red, 3 blue and 2 green sections. What is the probability of not getting a yellow?


to find the probability to not get a yellow you have to know the total of color which is

1+2+3+2=8

and its 1 yellow

So the probability of not getting a yellow is 1/8


hope this help
4 0
3 years ago
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Evaluate 2y + 4 for y = 15.
postnew [5]

Answer: 34

Step-by-step explanation

7 0
3 years ago
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The area of a sector with a central angle of 30' is 150'. Determine the approximate length of the diameter.
ioda

Answer:

It looks different. Can you provide some formulae based on it. I may help you out in the comment section!

4 0
3 years ago
Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl
GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane n=(-2,-2,1), then r will have the next parametric equations:

x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3

Substitute the value of \lambda in the parametric equations:

x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u

7 0
3 years ago
PLS HELP!!
lord [1]

Answer:

The height of the cone-shaped cup is 6 inches and the diameter at the top is 3 inches. ... To find the volume of the cone, you use a formula similar to that of a pyramid, ... \begin{align*}V & = \frac{1}{3} \pi r^2 h \\ V & = \frac{1}{3} (3.14)(5^2 )(7) ... The answer is the volume of the cone is 183.16 cubic inches.

Step-by-step explanation:

i think thats it it was right on gogle

5 0
3 years ago
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