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Helga [31]
3 years ago
11

10.A car is travelling at a constant speed of 27m/s. The driver looks away from the road for a 2.0s to tune in a station on the

radio. How far does the car go during this time?
Physics
1 answer:
Korvikt [17]3 years ago
5 0

Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

d = 54 m

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how much water is needed to produce 1kwh of electricity at a power plant that is 30% efficient if the temperature increase 10 C
Dimas [21]

The amount of water needed is 287 kg

Explanation:

The amount of energy that we need to produce with the power plant is

E=1 kWh = (1000W)(1h)=(1000W)(3600s)=3.6\cdot 10^6 J

We also know that the power plant is only 30% efficient, so the energy produced in input must be:

E_{in}=\frac{E}{0.30}=\frac{3.6\cdot 10^6}{0.3}=1.2\cdot 10^7 J

The amount of water that is needed to produce this energy can be found using the equation

E_{in}=mC\Delta T

where:

m is the amount of water

C=4186 J/kg^{\circ}C is the specific heat capacity of water

\Delta T=10^{\circ}C is the increase in temperature

And solving for m, we find:

m=\frac{E_{in}}{C\Delta T}=\frac{1.2\cdot 10^7}{(4186)(10)}=287 kg

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

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3 0
3 years ago
An environmental scientist gives a demonstration on composting. Roger is in the audience. He wonders how composting discarded fo
Wittaler [7]

Answer:

A

Explanation:

I just did the test

4 0
3 years ago
Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight dow
bulgar [2K]

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

F=\frac{\Delta p}{\Delta t}

where

F is the force exerted

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be rewritten as

\Delta p = m(v-u)

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

F=\frac{m(v-u)}{\Delta t}

In this problem we have:

\frac{m}{\Delta t}=0.030 kg/s is the mass rate

u=-15 m/s is the initial velocity

v=+15 m/s is the final velocity

Therefore, the force exerted by the hail on the roof is:

F=(0.030)(+15-(-15))=0.9 N

6 0
3 years ago
What is the Mirror equation? What does it look like?
kipiarov [429]

Answer:

1/f = 1/D' + 1/D

The magnification equation relates the ratio of the image distance and object distance to the ratio of the image height (h^i) and object height (h^o). The magnification equation is stated as follows:

M= H^i/H^o = D^i/D^o

7 0
3 years ago
Which resultant force is NOT possible if 50 N force and a 60 N force act concurrently?
Sergio [31]

Answer:

The options are not shown, so i will answer in a general way.

Suppose the case where the forces act in opposite directions, then we need to subtract the forces, and we know that the magnitude of the resultant force will be:

60N - 50N = 10N

Now, suppose the case where both forces act in the exact same direction, in that case, we will add the forces to get:

60N + 50N = 110N

Then the only range of forces that we can get in this system, are the forces such:

10N ≤ F ≤ 110N

Any resultant force outside that range is not possible in this situation.

3 0
3 years ago
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