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Helga [31]
3 years ago
11

10.A car is travelling at a constant speed of 27m/s. The driver looks away from the road for a 2.0s to tune in a station on the

radio. How far does the car go during this time?
Physics
1 answer:
Korvikt [17]3 years ago
5 0

Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

d = 54 m

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Answer: Resistance =3.2 \Omega , Current = 1.56 A, Voltage =4.99 V

The resistance,

R=\frac {\rho l}{A}

where, \rho is resistivity, A is the area and l is the length of the resistor.

It is given that:

\rho=1.0\times10^{-3}\Omega m

Length, l=2 mm

Area, A= width \times height=1.25 mm\times 0.5 mm=0.625 mm^2

Hence, R=\frac{1.0\times10^{-3}\Omega m \times 2\times10^{-3}m}{0.625\times10^{-6}m^2}=3.2\Omega

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4 0
3 years ago
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castortr0y [4]
The potential energy of the block is given by:
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h height

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k spring constant
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If the block starts from rest it has potential energy, but no kinetic energy. As it slides down the incline potential energy is converted into kinetic energy. When the block hits the spring the kinetic energy is converted into spring's potential energy. If the spring is fully compressed and the block is at rest again, the block has transferred all its energy into the spring. No energy is lost. So we can write:

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