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Nuetrik [128]
3 years ago
10

Research is being done on the use of radio waves in destroying cancer cells. What type of frequency would be best used in this t

echnology?
Physics
1 answer:
shusha [124]3 years ago
8 0

Answer:

Radiofrequency Ablation (RFA) which is a type of Electrical Energy is used to treat cancer. If it sees heat made by radio waves to kill cancer cells. Ablation means destroying completely. The method is putting RFA a probe (electrode) that goes through the skin into the tumor. A CT scan is needed so to check that the probe is in exactly the right place. An electrode in the probe creates radiofrequency energy to produce heat and kill the cancer cells.

Explanation:

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Answer:

A

Explanation:

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Why is the rotation system used in volleyball? Physics was the closest thing to PE
tankabanditka [31]

Answer:

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Using a 683 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t
n200080 [17]

Answer:

10.2 m

Explanation:

The position of the dark fringes (destructive interference) formed on a distant screen in the interference pattern produced by diffraction from a single slit are given by the formula:

y=\frac{\lambda (m+\frac{1}{2})D}{d}

where

y is the position of the m-th minimum

m is the order of the minimum

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light used

In this problem we have:

\lambda=683 nm = 683\cdot 10^{-9} m is the wavelength of the light

d=1.1 mm = 0.0011 m is the width of the slit

m = 13 is the order of the minimum

y=8.57 cm = 0.0857 m is the distance of the 13th dark fringe from the central maximum

Solving for D, we find the distance of the screen from the slit:

D=\frac{yd}{\lambda(m+\frac{1}{2})}=\frac{(0.0857)(0.0011)}{(683\cdot 10^{-9})(13+\frac{1}{2})}=10.2 m

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X = 20 <br> v = 3.5 m/s <br> t = ?
N76 [4]

Answer:

16.5 I think

Explanation:

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