3 years ago

Solve for x: 0= 2y^2-8y-10

Mathematics

1 answer:

Nutka1998 [239]3 years ago

5 0

Answer:

x=5, -1

Step-by-step explanation:

I think you mean 2x^2-8x-10=0

2x^2-8x-10=0

Factor out a 2 (0/2 is still 0)

2(x^2-4x-5)=0

Divide by 2

x^2-4x-5=0

Find something that MULTIPLIES to get -5 and ADDS up to get -4, then factor

(x-5)(x+1)=0

Make each set =0

x-5=0

x+1=0

x=5, -1

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