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katen-ka-za [31]
3 years ago
8

Solve for x: 0= 2y^2-8y-10

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

x=5, -1

Step-by-step explanation:

I think you mean 2x^2-8x-10=0

2x^2-8x-10=0

Factor out a 2 (0/2 is still 0)

2(x^2-4x-5)=0

Divide by 2

x^2-4x-5=0

Find something that MULTIPLIES to get -5 and ADDS up to get -4, then factor

(x-5)(x+1)=0

Make each set =0

x-5=0

x+1=0

x=5, -1

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6 times the sum of 3 consecutive odd intergers is -18
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The answer: The 3 (three) consecutive odd integers are: -3, -1, 1.
_____________________________________________
Explanation:
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To represent 3 (three consecutive odd integers):
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Let "x" be the first odd integer.
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Let "(x+2)" be next consecutive odd integer.
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Let "(x+4") be the third odd integer.
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The sum of these three consecutive odd integers:
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x + (x + 2) + (x + 4) = x + x + 2 + x + 4 = 3x + 6 ;
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Six ("6") times the sum of these 3 (three) consecutive odd integers =
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6*(3x+6) = 6(3x + 6) = -18 (as given in the problem).
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Given: 6(3x + 6) = -18 ; We can divide EACH SIDE of the equation by "6", to cancel the "6" on the left-hand side into a "1"; 
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{6(3x + 6) } / 6 = -18 / 6 ;  to get:
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3x + 6 = -3 ; Now, we can subtract "6" from EACH SIDE of the equation:
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3x + 6 - 6 = -3 - 6 ; to get:
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3x = -9 ; Now, we can divide EACH SIDE of the equation by "3"; to isolate "x" on one side of the question; and solve for "x" ;
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3x / 3 = -9 / 3 ;  x = - 3 ;
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Remember, from above:
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Let "x" be the first odd integer.  We know that "x = -3".
         Is this an odd integer? Yes!
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Let "(x+2)" be next consecutive odd integer.  So (x+2) = (-3+2) = -1.
        Is this an odd integer? Yes!  Is this "{-1}" the next consecutive odd integer with respect to "{-3}"? Yes!
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Let "(x+4") be the third odd integer. So (x+4) = (-3+4) = 1.
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So, our 3 (three) consecutive odd integers are: -3, -1, 1.
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To check our work: Is 6 times the sum of our 3 consecutive odd integers, equal to "(-18)" ?

The sum of our 3 consecutive odd integers = -3 + (-1) + 1 = -3 - 1 + 1 = -3.

6 * -3 = ? -18? Yes!
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3 years ago
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