perpendicular lines have a slope that is a negative reciprocal
A) 4x-5y=5
subtract 4x
solve for y
-5y = -4x+5
divide by -5
y = 4/5 x+5 slope is 4/5 perpendicular slope is -5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = -5/4 (x-5)
B) 5x+4y = 37
subtract 5x
4y =-5x +37
divide by 4
y =-5/4 x +37/4 slope is -5/4 perpendicular slope is 4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = 4/5 (x-5)
C)4x+5y=5
subtract 4x
5y = -4x +5
divide by 5
y = -4/5 x +1
y =-4/5 x +1 slope is -4/5 perpendicular slope is 5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = 5/4 (x-5)
D)5x-4y=8
subtract 5x
-4y = -5x+8
divide by -4
y = 5/4 x-2
y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = -4/5 (x-5)
Answer:
x = 4
Step-by-step explanation:
Given
2(3x - 5) = 2x + 6 ( divide both sides by 2 )
3x - 5 = x + 3 ( subtract x from both sides )
2x - 5 = 3 ( add 5 to both sides )
2x = 8 ( divide both sides by 2 )
x = 4
The answer is w⁻²/v⁻².
v/w raised to the second power is (v/w)²
(v/w)² = v²/w²
Since xᵃ = 1/x⁻ᵃ, then v²/w² = 1/v⁻²w²
Since 1/xᵃ = x⁻ᵃ, then 1/v⁻²w² = w⁻²/v⁻²
I think the answer is 2.25 or 2 and 1/4.
You divide 3/4 by 1/3 and get 2.25 or 2 and 1/4.
I don't know if this is right, I hope it is, have a good day. c;
X + (4x+15) = 180
5x+15=180
5x=165
x=33
4(33)+15=147. (Or you could subtract 33 from 180)
Check answer: 33+147=180 yes
