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3 years ago

How far apart are the foci of an ellipse with a major axis of 26 feet and a minor axis of 24 feet?

Mathematics

2 answers:

Tom [10]3 years ago

6 0

The distance should be 10 feet

aleksley [76]3 years ago

3 0

<span>Let the major axis = 2a , and the minor axis = 2b
∴ a = 26/2 = 13 and b = 24/2 = 12
and the equation of foci:
c² = a² - b²
= 13² - 12² = 169 - 144 = 25
∴ c = √25 = 5

∴ The distance between the foci = 2 * 5 = 10
</span>

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finlep [7]

The Answer Is 540 Feet.

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3 years ago

Which ordered pair is a solution of the equation? y=-2x+5y=−2x+5 (Choice A) A Only (2,-9)(2,−9) (Choice B) B Only (-2,9)(−2,9) (

Firdavs [7]

Answer:

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Step-by-step explanation:

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4 years ago

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2 years ago

Write an equation with a variable AND solve it. Mario read 72 pages of his book in class and 13 pages per night, n, until he rea

coldgirl [10]

9514 1404 393

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72 +13n = 163

7 nights

Step-by-step explanation:

At 13 pages per night, Mario will read 13n pages in n nights. That plus the pages already read will total 163:

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To solve this, we can subtract 72, then divide by the coefficient of n.

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3 years ago

X-1/x-2+x+3/x-4=2/(x-2).(4-x)

Varvara68 [4.7K]

The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

According to the statement

we have given that the equation and we have to prove that the given answer is a correct answer for those equivalent equation.

So, The given expression are:

$\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}$

And we have to prove the answer.

So, For this

$\frac{x-1}{x-2} +\frac{x+3}{x-4}$

$\frac{({x-1}) ({x-4}) +({x+3})({x-2})} {(x-2) (x-4)}$

Then the equation become

$\frac{x^{2} -4x -x +4 + x^{2} -2x + 3x -6 }{(x-2) (x-4)}$

Now solve it then

$2x^{2} - 4x -2 / (x-2) (x-4)$

Now take 2 common from answer then equation become

$\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}$

Hence proved.

So, The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

Learn more about equations here

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1 year ago