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Jlenok [28]
3 years ago
9

How far apart are the foci of an ellipse with a major axis of 26 feet and a minor axis of 24 feet?

Mathematics
2 answers:
Tom [10]3 years ago
6 0
The distance should be 10 feet
aleksley [76]3 years ago
3 0
<span>Let the major axis = 2a , and the minor axis = 2b
∴ a = 26/2 = 13    and   b = 24/2 = 12
and the equation of foci:
c² = a² - b²
    = 13² - 12² = 169 - 144 = 25
∴ c = √25 = 5

∴ The distance between the foci = 2 * 5 = 10
</span>
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Which pair of terms are like terms?
sdas [7]

Answer:

b: -2y and 4y

Step-by-step explanation:

The answer is option B

-2y and 4y are like terms because they have the same algebraic alphabet at the back of their coefficients.

6 0
3 years ago
E=6c^2-2c-1<br> F=-4c^2+7c+5<br> E+F=
kifflom [539]

Answer:

E + F =   2c^2  + 5c + 4

Step-by-step explanation:

E=6c^2-2c-1

F=-4c^2+7c+5

E+F=  6c^2   -2c   -1  +  -4c^2   +   7c   +  5

E + F =   6c^2 - 4c^2  - 2c + 7c  - 1  + 5

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4 0
3 years ago
Points showing equivalent relics on the coordinate planeten
koban [17]

Answer:

<em>Answer: (8,12) Third option</em>

Step-by-step explanation:

<u>Equivalent Ratios</u>

Nardia plotted some points showing equivalent ratios. The points shown in the graph are: (2,3), (4,6), (10,15)

The ratios of the points in the form y:x are:

\frac{3}{2}

\frac{6}{4}=\frac{3}{2}

\frac{15}{10}=\frac{3}{2}

Note all the ratios are equivalent.

From the ordered pairs provided in the choices, only one of them has the same ratio y:x.

Point (12,8) has a ratio:

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3 0
3 years ago
What is 5/6divided by 30/60
bearhunter [10]
It would be: 5/6 / 30/60
We can re-write it as: 5/6 * 60/30
= 1/1 * 10/6
= 5/3

In short, Your Answer would be 5/3 or 1 2/3 or 1.67

Hope this helps!
5 0
3 years ago
Please help!
erik [133]
For the answer to the question above, 
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3 

<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

<span>(1+x) = 0.98 </span>

<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>

<span> (0.98)^9 = 0.8337477621 </span>

<span>So it is correct to 4</span>
5 0
3 years ago
Read 2 more answers
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