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2 years ago

The LCM of 13 and 9

Mathematics

1 answer:

babymother [125]2 years ago

4 0

Answer:

The Least Common Multiple of 13 and 9 is 13×9=117 because 13 is prime so they share no factors to create multiples of.

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Factor the expression completely. 2-12x

Nikitich [7]

Answer:

2(1 - 6x)

Step-by-step explanation:

2-12x

Common factor: 2

Factored equation:

2(1 - 6x)

7 0

2 years ago

Two vectors vector a and vector b have precisely equal magnitudes. in order for the magnitude of vector a + vector b to be 110 t

Anika [276]

<h3>Given</h3>

Vector A = (Vector B)×(1∠α)

|A+B| = 110×|A-B|

angle α

<h3>Solution</h3>

Substituting for vector A in the given relation, we have

... |B×(1∠α) + B| = 110|B×(1∠α) -B|

Now 1∠α in polar coordinates is (cos(α), sin(α)) in rectangular coordinates.

Dividing by |B|, we have the relation between sum and difference vector magnitudes is

... √((1 +cos(α))² +sin(α)²) = 110√((cos(α) -1)² +(-sin(α))²)

Squaring both sides gives

... 1 +2cos(α) +cos(α)² +sin(α)² = 12100(1 -2cos(α) +cos(α)² +sin(α)²)

... 1 +cos(α) = 12100(1 -cos(α)) . . . . using sin²+cos²=1 and dividing by 2

And solving for cos(α) gives

... cos(α)(1+12100) = 12100 -1

... α = arccos(12099/12101) ≈ 1.0417°

The angle between the vectors is about 1.0417°.

4 0

3 years ago

Let’s say we want to find the size of a deer population. Suppose that we capture 80 deer, tag them, and release them back into t

lorasvet [3.4K]

Answer:

400

Step-by-step explanation:

20/100 = 80/x

Cross multiply and divide

100 X 80 = 8000 / 20 = 400

8 0

2 years ago

Read 2 more answers

50 POINTS FIRST GOOD ANSWER GETS BRAINLIEST

Inessa [10]

Answer:

$f(x)=3+|2x-5|=\left\{ \begin{array}{ll} 2x-2& \quad x \geq 5/2 \\ -2x+8 & \quad x < 5/2 \end{array} \right.$

Step-by-step explanation:

We are given the function:

$f(x)=3+|2x-5|$

Remember that by the definition of absolute value:

$\displaystyle |x|= \left\{ \begin{array}{ll} x & \quad x \geq 0 \\ - x & \quad x < 0 \end{array} \right.$

Our absolute value is:

$|2x-5|$

First, we will find when it becomes 0. Set the equation equal to 0:

$2x-5=0$

Solve for <em>x: </em>

<em />

So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.

For all values less than <em>x </em>= 5/2, 2x - 5 is negative.

Therefore (the positive case go above, and the negative case go below):

$|2x-5|= \left\{ \begin{array}{ll} 2x-5 & \quad x \geq 5/2 \\ -(2x-5) & \quad x < 5/2 \end{array} \right.$

Finally, we can add a three:

$f(x)=3+|2x-5|=\left\{ \begin{array}{ll} 3+(2x-5) & \quad x \geq 5/2 \\ 3+(-(2x-5)) & \quad x < 5/2 \end{array} \right.$

Simplify if desired:

$f(x)=3+|2x-5|=\left\{ \begin{array}{ll} 2x-2& \quad x \geq 5/2 \\ -2x+8 & \quad x < 5/2 \end{array} \right.$

5 0

2 years ago

Maximo types 180 words in two minutes. How many words does he type in 7 minutes?

aleksklad [387]

Answer:

630 just divide 180 by 2, you'll get 90 the multiply it by 7

8 0

2 years ago

Read 2 more answers