Hello!
A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution ?
We have the following data:
M1 (initial molarity) = 0.100 M (or mol/L)
V1 (initial volume) = 2.00 L
M2 (final molarity) = 1.75 M (or mol/L)
V2 (final volume) = ? (in L)
Let's use the formula of dilution and molarity, so we have:






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