93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0C what would be the volume of this dry gas at STP
1 answer:
The volume of the dry gas at stp is calculated as follows
calculate the number on moles by use of PV =nRT where n is the number of moles
n is therefore = Pv/RT
P = 0.930 atm
R(gas contant= 0.0821 L.atm/k.mol
V= 93ml to liters = 93/1000= 0.093L
T= 10 + 273.15 = 283.15k
n= (0.930 x0.093) /(0.0821 x283.15) = 3. 72 x10^-3 moles
At STp 1 mole = 22.4L
what about 3.72 x10^-3 moles
by cross multiplication
volume = (3.72 x10^-3)mole x 22.4L/ 1 moles = 0.083 L or 83.3 Ml
You might be interested in
Answer:
The answer is
<h2>25 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of CCl4 = 40g
Density = 1.6 g/mL
The volume is
We have the final answer as
<h3>25 mL</h3>
Hope this helps you
Combination therapy is the most effective treatment for HIV. I hope this help
Answer:
Breaks down and absorbs nutrients from the food and liquids you consume to use for important things like energy, growth and repairing cells.
Scandium lost 3 electrons and gave them to oxygen the formula would be Sc2O3
2Al₂O₃ → 4Al + 3O₂
the mole ratio is 4:3
for every 4 Al, there must be 3 O₂ in order to make 2Al₂O₃
hope this helped at all
