Answer:
It would be 2.323167848877082
Explanation:
Answer:
A) 9.60 g
B) 19.2 g
C) 28.8 g
Explanation:
A) Elemental oxygen mass is 16.00 g/mol, so in 0.600 mol of elementar oxygen there is 9.60 g
0.600 mol x 16.00 g/mol=9.60 g
B) Oxygen molecular mass is 32.00 g/mol, so in 0.600 mol of oxygen molecules there is 19.2 g
0.600 mol x 32.00 g/mol=19.2 g
C) Ozone molecular mass is 48.00 g/mol, so in 0.600 mol of oxygen molecules there is 28.8 g
0.600 mol x 48.00 g/mol=28.8 g
Answer:
I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.
n = 5 4th excited state
n = 4 3rd excited state
n = 3 2nd excited state
n = 2 1st excited state
n = 1 ground state
Here are the possible spectral lines.
n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.
n = 4 to 3, 4 to 2, 4 to 1 = 3 lines
n = 3 to 2, 3 to 1 = 2 lines
n = 2 to 1 = 1 line. Add 'em up. I get 10.
b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.
c.The E for any level is -21.8E-19 Joules/n^2
To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.
So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.
Explanation:
Answer:
Its properties remain unchanged as it is undergoing physical changes.
Explanation:
Hello.
In this case, since aluminum foil is made up of aluminum leaves having a 0.2-mm thick it is widely known that is deformed when wrinkled due to its tiny average thick. Moreover, when cut half over and over again smaller pieces are obtained every time it is done. Nevertheless, even when its shape and size can be modified via physical actions, its properties remain unchanged because cutting is a physical change which is not affecting its chemical composition.
Best regards.
