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ki77a [65]
3 years ago
12

What two positive real numbers whose product is 50 have the smallest possible sum?

Mathematics
1 answer:
Llana [10]3 years ago
7 0
X * y = 50
y = 50 / x
S = x + y = x + 50 / x
S` = 1 - 50 / x²
1 - 50 / x² = 0
50 / x² = 1
x² = 50
x = √ 50 = 5 √2
y = 50 / 5√2 = 5 √2
Answer:
Those numbers are: x = 5√2 and y = 5√2.
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4X^2 - 8X + 4<br> - (2x^2 - 3X + 7 =
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I assume the way it's written is like this

4x^2 - 8x + 4 - (2x^2 - 3x + 7)

If that's the case, just combine like terms.

Let's begin with 4x^2. It has the same components as the -2x^2 (remember, since it's being subtracted in the original equation, the number is negative.)

4x^2 - 2x^2 = 2x^2

Now -8x and 3x (be careful, sometimes there's a minus sign in and out of the parentheses, this makes the number positive again

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Hope this helped! If you need me to explain anything, don't be afraid to ask.
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