Answer:
Step-by-step explanation:
Given that:
There are 3 sizes of dishwasher soaps.
Twenty percent of all purchasers select a 25-oz box, 50% select a 40-oz box, and the remaining 30% choose a 65-oz box. Let X1 and X2 denote the package sizes selected by two independently selected purchasers.
Therefore,  random samples of size 2 are taken from the population.
 random samples of size 2 are taken from the population.
The information is well represented in the table below.
 
      
      
     
     
25    25    0.20×0.20=0.04        25                              0
25    40    0.20×0.50=0.10         32.5                         112.5
25    65    0.20×0.30= 0.06        45                            800
40    25    0.50×0.20=0.10         32.5                          112.5
40    40    0.50×0.50=0.25         40                             0
40    65    0.50×0.30=0.15          52.5                         312.5
65    25    0.30×0.20=0.06        45                             800
65    40    0.30×0.50=0.15          52.5                         312.5
65    65    0.30×0.30=0.09         65                              0
The sample distribution of  is shown below as ;
 is shown below as ;
 25        32.5              40       45                  52.5          65
           25        32.5              40       45                  52.5          65
 0.04   0.10+0.10      0.25   0.06+0.06    0.15+0.15    0.09
       0.04   0.10+0.10      0.25   0.06+0.06    0.15+0.15    0.09    
                        = 0.20                      =0.12              =0.30
The value of 
=  25(0.04) + 32.5(0.20) + 40(0.25) + 45(0.12)  +  52.5(0.30)  +  65(0.09) 
= 44.5 oz
From the same table above ;
the sampling distribution of  is be shown below;
 is be shown below;
 0                          112.5            312.5             800
          0                          112.5            312.5             800
            0.04+0.25       0.10+0.10     0.15+0.15        0.06+0.06
           +0.09 
 = 0.38                =0.20           = 0.30               0.12
   = 0.38                =0.20           = 0.30               0.12
The value of 
= (0×0.38)+(112.5×0.20)+(312.5×0.30)+(800×0.12)
=0+112+93.75+96
=301.75