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ki77a [65]
3 years ago
12

What two positive real numbers whose product is 50 have the smallest possible sum?

Mathematics
1 answer:
Llana [10]3 years ago
7 0
X * y = 50
y = 50 / x
S = x + y = x + 50 / x
S` = 1 - 50 / x²
1 - 50 / x² = 0
50 / x² = 1
x² = 50
x = √ 50 = 5 √2
y = 50 / 5√2 = 5 √2
Answer:
Those numbers are: x = 5√2 and y = 5√2.
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U.s. air has a net income before tax 60,000. it is expected 45% of net income will go to federal and state taxes. how much will
muminat
60,000 times .45= 27000
60,000-27,000= 33,000
US air will have $30,000 left after federal and state taxes
3 0
3 years ago
3+x) 5<br> Solve it for me, and tell me how to do it EXPLANATION NEEDED
grigory [225]
I’m not too sure of what the equation is but I made a guess let me know if this was the right equation please I can redo it.

But, when solving this equation you are trying to find the value of x. To do that you have to get rid of the 3.

You would either add or subtract the 3 on both sides.

When the three is gone you should have somthing like

x = 5
- 3

Which you would move on to subtract the 5-3 and get 2.

x= 2

Here’s a picture of how I solved it
3 0
3 years ago
a library has an average of 510 visitors on Sundays and 240 visitors on other days. The average number of visitors per day in a
serious [3.7K]

Answer:

285

Step-by-step explanation:

hi

personally this is how i would do this question but there are other ways.

i would start off by seeing how many sundays there are in the month (which is 5) then the number of other days which is 25. i'd then multiply 5 by 510 which is 2550. add that to 240 times 25 (which is 6000) and all of that together is 8550. divide that by the number of the days in the month (30) and then you'll get the daily avergae for the month

hope this helped:)

6 0
3 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
2 years ago
Find the range and interquartile range for the data represented by the box plot.
Anarel [89]

<u>Given</u>:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

<u>Range:</u>

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

<u>Interquartile range:</u>

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

3 0
3 years ago
Read 2 more answers
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