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lana [24]
3 years ago
7

Tell whether the ordered pair (2, 5) is a solution of the system of linear equations.

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
Yes it is because you replace the 2 for the x and the 5 for the y.
2+5=7
7=7
2(2)-3(5)=-11
4-15=11
-11=-11
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A pair of weak earthquakes is modeled by a system of inequalities. One earthquake occurred roughly 20 km east and 14 km north of
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Answer:

2 km east and 10 km north

Step-by-step explanation:

I did the activity and got the right answer.

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Flura [38]

Answer:

D) cot(C) = 1/2.

Step-by-step explanation:

We can go through each choice and examine is validity.

Choice A)

We have:

\displaystyle \sec B=\frac{3}{7}

Recall that secant is the ratio of the hypotenuse to the adjacent.

With respect to B, the adjacent is 6 and the hypotenuse is 7.

Therefore, sec(B) should be 7/6 instead.

A is incorrect.

Choice B)

We have:

\displaystyle \cot B=\frac{3}{2}

Cotangent is the ratio of the adjacent side to the opposite.

With respect to B, the adjacent side is 6 and the opposite side is 3.

Therefore, cot(B) = 6/3 = 2.

B is incorrect.

Choice C)

C is incorrect for the reasons listed in A.

Choice D)

We have:

\displaystyle \cot C=\frac{1}{2}

Again, cotangent is the ratio of the adjacent side to the opposite.

With respect to C, the adjacent side is 3 and the opposite side is 6.

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Therefore, D is the correct choice!

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3 years ago
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KatRina [158]
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The one-to-one functions g and h are defined as follows
Debora [2.8K]

Answer:

g^-^1(x)=-8

h^-^1(x)=\frac{x-4}{3}

(h^-^1 \ o\ h)(-3)=-3

Step-by-step explanation:

When given the following functions,

g=[(-2,-7),(4,6),(6,-8),(7,4)]

h(x)=3x+4

One is asked to find the following,

1. Question 1

g^-^1(4)

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

g^-^1(4)

g(4)=6\\g(6)=-8\\g^-^1(4)=-8

2. Question 2

h^-^1(x)

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)

h^-^1(x)=\frac{x-4}{3}

3. Question 3

(h^-^1 \ o\ h)(-3)

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function (h^-^1) and simplify. Then substitute (-3) into the result.

h^-^1\ o\ h

\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x

Now substitute (-3) in place of (x),

=-3

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Check the picture below.

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