All categories

4 years ago

Why does NaCl have a high melting point but readily dissolves in water?

Chemistry

1 answer:

Gre4nikov [31]4 years ago

6 0

NaCl IS READILY SOLUBLE IN WATER DUE TO HIGH HYDRATION ENERGY

BUT HAVE HIGH MELTING POINT DUE TO STRONG ELECTROSTATIC FORCE BETWEEN SODIUM AND CHLORIDE IONS.

Explanation:

Sodium has low melting point 98 deg celcius. In water sodium gets floated.

But sodium chloride have a high melting point because lattice is constructed due to strong electro-static force between positive sodium ions and negative chloride ions as they attract each other. This leads to strong construction so, NaCl have high temperature to break the bonds between the ions.

The melting temperature depends on the charge of the ions. Due to high hydration energy the sodium ions are readily soluble in water. Water can dissolve salt because the positive part of water molecules attracts negative chloride ions and negative part of water molecules attracts positive sodium ions.

You might be interested in

The symbols used on a map are explained in the

Nady [450]

Answer - LEGEND

The legend of a map is also called the map key. It is the part included in a map to, as it were, unlock the map. The legend (or map key) gives explanation to what each symbol and color used in the map represents.

5 0

4 years ago

The density of a 20.3 m ch3oh (methanol) solution is 0.858 g/ml. what is the molality of this solution? h2o is the solvent.

aliina [53]

The difference of molarity and molality is in the units:

Molarity is expressed in mol solute / L solution;

<span> while Molality is expressed in mol solute / kg solvent</span>

Since no other data is given, let us assume that the contribution of methanol on the total volume is negligible. So that,

Molality = (20.3 mol / L) (1 L / 0.858 kg)

Molality = 23.66 m

<span>The closest answer is letter C. 23.7 m</span>

6 0

4 years ago

Please help... awarding 20 points and brainiest if correct.

kiruha [24]

Answer:

CH4

- 4 electron

- 0 electron

- the geometry of Ch4 is tetrahedral

AlF3

- 3 electron

- 0 electron

- the geometry is trigonal planar

CCl4

- 4 electron

- 0 electron

- the geomotry is tetrahedral

SeH2

- 2 electron

- the geometry is V shape

5 0

3 years ago

You want to prepare 500.0 mL of 1.000 M KNO3 at 20°C, but the lab (and water) temperature is 24°C at the time of preparation. Ho

timama [110]

Explanation:

As per the given data, at a higher temperature, at $24^{o}C$ , the solution will occupy a larger volume than at $20^{o}C$ .

Since, density is mass divided by volume and it will decrease at higher temperature.

Also, concentration is number of moles divided by volume and it decreases at higher temperature.

At $20^{o}C$ , density of water=0.9982071 g/ml

Therefore, $\frac{concentration}{density}$ will be calculated as follows.

= $\frac{C_{1}}{d_{1}}$

= $\frac{1.000 mol/L}{0.9982071 g/ml}$

= 1.0017961 mol/g

At $24^{o}C$ , density of water = 0.9972995 g/ml

Since, $\frac{concentration}{density}$ = $\frac{C_{2}}{d_{2}}$

= $\frac{C_{2}}{0.9972995}$

Also, $\frac{C_{1}}{d_{1}}$ = $\frac{C_{2}}{d_{2}}$

so, 1.0017961 mol/g = $\frac{C_{2}}{0.9972995}$

$C_{2} = 1.0017961 \times 0.9972995$

= 0.9990907 mol/L

Therefore, in 500 ml, concentration of $KNO_{3}$ present is calculated as follows.

$C_{2}$ = $\frac{concentration}{volume}$

0.9990907 mol/L = $\frac{concentration}{0.5 L}$

concentration = 0.49954537 mol

Hence, mass (m'') = $0.49954537 mol \times 101.1032 g/mol$ = 50.5056 g (as molar mass of $KNO_{3}$ = 101.1032 g/mol).

Any object displaces air, so the apparent mass is somewhat reduced, which requires buoyancy correction.

Hence, using Buoyancy correction as follows,

m = $m''' \times \frac{(1 - \frac{d_{air}}{d_{weights}})}{(1 - \frac{d_{air}}{d})}}$

where, $d_{air}$ = density of air = 0.0012 g/ml

$d_{weight}$ = density of callibration weights = 8.0g/ml

d = density of weighed object

Hence, the true mass will be calculated as follows.

True mass(m) = $50.5056 \times \frac{(1 - \frac{0.0012}{8.0})}{(1 - (\frac{0.0012}{2.109})}$

true mass(m) = 50.5268 g

= 50.53 g (approx)

Thus, we can conclude that 50.53 g apparent mass of $KNO_{3}$ needs to be measured.

8 0

3 years ago

HELPP PLEASEEEEEEE ITS PROBS EASY FOR YOU GUYS

hichkok12 [17]

Answer:

ik that energy makes us movie and that it powers lights and electronics

kinetic energy ,chemical energy ,potential energy ,and thermal energy

the law of conservation of energy states that the total energy of an isolated system remains constant

Explanation:

hope it helpss

5 0

4 years ago

Read 2 more answers