Answer:
very hard others will answer it
Explanation:
hard
There's no air in space, so there's no air resistance there.
Answer:
1.) 11 km/s
2.) 9.03 × 10^-5 metres
Explanation:
Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.
Electron q = 1.6×10^-19 C
Electron mass = 9.11×10^-31 Kg
(a) What is the speed of the electron 1.3 ns after entering this region?
E = F/q
F = Eq
Ma = Eq
M × V/t = Eq
Substitute all the parameters into the formula
9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19
V = 7.68×10^-18 /7.0×10^-22
V = 10971.43 m/s
V = 11 Km/s approximately
(b) How far does the electron travel during the 1.3 ns interval?
The initial velocity U = 64 km/s
S = ut + 1/2at^2
S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2
S =8.32×10^-5 + 7.13×10^-6
S = 9.03 × 10^-5 metres
I believe scattering is what occurs when light essentially changes direction after colliding with small particles of matter.
This type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
<h3>
What is open system?</h3>
An open system is a type of system that has external interactions which means energy, or material transfers into or out of the system.
So we can conclude that this type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
Learn more about system here: brainly.com/question/14323743
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