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3 years ago

PLEASE HELP FAST!! WILL MARK AS BRAINLIEST IF GIVEN GOOD ANSWER

Mathematics

2 answers:

Masteriza [31]3 years ago

8 0

Answer:

80 degrees

Step-by-step explanation:

both intersections are the same, so we can count them as one. We notice that one line is a straight line compared to other so we can subtract 100 from 180 and get 80

mario62 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Vertical angles equal 360 in total and the angles across from each other equal the same. 100 x 2 = 200

360-200 = 160

160/2 = 80

I hope this helps enjoy your day!

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$65 dress pants 20% discount

jeka57 [31]

20% of 65 = 65 * 1/5, which is 13. so 20% of 65 is $13. so a discount of 20% = 65-13 which is $52

8 0

3 years ago

Read 2 more answers

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

3 years ago

Using the triangle below, find the ratio please need help answering for a quiz

Murrr4er [49]

As we know that , sinA = opposite/hypotenuse & tanA = opposite/adjacent

So here we can find sin22° , because they already given the sides opposite & hypotenuse . And we can't find tann22° because they given the value of opposite but not given the value of adjacent side of the angle 22°

Now finding the adjacent side using

Pythagoras theorem :-

• Hypotenuse² = Base² + Height²

=> 40² = Base² + 15²

=> 1600 - 225 = Base²

=> Base² = 1375

=> Base = √1375

=> Base = 5√55

Now ,