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aleksley [76]
3 years ago
12

Solve 3.4 [ 6 ( 4) +6^2] Please show your work! <3

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

204

Step-by-step explanation:

3.4[6(4)+6^2]=

3.4[24+36]=

3.4[60]=

204

Hope this helps!

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In a semiconductor company's quality control test, a machine found that 14 out of a sample of 234 computer chips were defective.
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-3 > v     v > 11

Step-by-step explanation:


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How many three 3 letter word can we make with the letter in the world post
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6

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How many subsets are there of the set N = {1, 42, 65, 12, 31, 27}?
lutik1710 [3]

Answer:

\boxed{ \bold{  \huge{ \boxed{ \sf{64}}}}}

Step-by-step explanation:

If ' n ' is the cardinal number of a set, the number of subsets of a given set can be obtained by using the formula 2ⁿ

Given,

N = { 1 , 42 , 65 , 12 , 31 , 27 }

where n ( total number of elements ) = 6

So, the number of possible subsets of set N :

= 2ⁿ

= 2⁶

= 2 × 2 × 2 × 2 × 2 × 2

= 64

Hope I helped!

Best regards!!

4 0
3 years ago
The judiciary committee at a college is made up of three faculty members and four students. If ten faculty members and 25 studen
Andre45 [30]

Answer:

1,518,000 committees.

Step-by-step explanation:

We have been given that the  judiciary committee at a college is made up of three faculty members and four students. Ten faculty members and 25 students have been nominated for the committee.

We will use combinations for solve our given problem.

^nC_r=\frac{n!}{r!(n-r)!}, where,

n = Number of total items,

r = Items being chosen at a time.

^{10}C_3\cdot ^{25}C_4=\frac{10!}{3!(10-3)!}\cdot \frac{25!}{4!(25-4)!}

^{10}C_3\cdot ^{25}C_4=\frac{10!}{3!*7!}\cdot \frac{25!}{4!*21!}  

^{10}C_3\cdot ^{25}C_4=\frac{10*9*8*7!}{3*2*1*7!}\cdot \frac{25*24*23*22*21!}{4*3*2*1*21!}

^{10}C_3\cdot ^{25}C_4=10*3*4\cdot 25*23*22

^{10}C_3\cdot ^{25}C_4=120\cdot 12650

^{10}C_3\cdot ^{25}C_4=1,518,000

Therefore, 1,518,000 judiciary committees could be formed at this point.

7 0
3 years ago
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