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siniylev [52]
3 years ago
11

a metalsmith is mixing two molten metals, each containing different percentages of silver. the table shows the amount of each mo

lten metal used. which two expressions are both equivalent to t, the total number of grams in the mixture?
Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0
It would be much easier if you attached a table. Anyway I know what you need to do. Just make an equation and put the numbers from the table given you in the task. And you'll solve it.
sineoko [7]3 years ago
7 0

(15)(0.75) and 0.7(15 - x) + 0.9x

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Complete the square to solve the equation below x2+2x-9=15
Ilia_Sergeevich [38]
A. x = -1; x = 3
B. x = 5; x = -4
C. x = -1; x = 4
D. x = -6; x = 4

: Hope this helps :)
7 0
3 years ago
×>10 is a solution to which inequality a}×-7>3 b}×-7>3 c}x-7<3 d}x-7<3
NeX [460]
A) x - 7 > 3    |add 7 to both sides
     x > 10

b) x - 7 > 3    |add 7 to both sides
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3 years ago
Equation 9(2j + 5j).<br><br><br> Use the distributive property to create an equivalent expression
raketka [301]

Answer:

63j

Step-by-step explanation:

Multiply 2j by 9 and 5j by 9. This gets you to 18j+45j. Then, add these since they are like terms: 63j.

4 0
3 years ago
I am having trouble with this relative minimum of this equation.<br>​
Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach.  You have to let me know if you want this done another way.

Here are some rules I'm going to use:

(f+g)'=f'+g'       (Sum rule)

(cf)'=c(f)'          (Constant multiple rule)

(x^n)'=nx^{n-1} (Power rule)

(c)'=0               (Constant rule)

(x)'=1                (Slope of y=x is 1)

y=4x^3+13x^2-12x-56

y'=(4x^3+13x^2-12x-56)'

y'=(4x^3)'+(13x^2)'-(12x)'-(56)'

y'=4(x^3)'+13(x^2)'-12(x)'-0

y'=4(3x^2)+13(2x^1)-12(1)

y'=12x^2+26x-12

Now we set y' equal to 0 and solve for the critical numbers.

12x^2+26x-12=0

Divide both sides by 2:

6x^2+13x-6=0

Compaer 6x^2+13x-6=0 to ax^2+bx+c=0 to determine the values for a=6,b=13,c=-6.

a=6

b=13

c=-6

We are going to use the quadratic formula to solve for our critical numbers, x.

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}

x=\frac{-13 \pm \sqrt{169+144}}{12}

x=\frac{-13 \pm \sqrt{313}}{12}

Let's separate the choices:

x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}

Let's approximate both of these:

x=0.3909838 \text{ or } -2.5576505.

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

f(x)=4x^3+13x^2-12x-56

f'(x)=12x^2+26x-12

f''(x)=24x+26

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here:  x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

24(-2.6)+25

-37.5  

So we have a maximum at x=-2.6.

24(.4)+25

9.6+25

34.6

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56

I'm shoving this into a calculator:

y=-58.4654411

So the approximate relative minimum is (0.4,-58.5).

If you graph y=4x^3+13x^2-12x-56 you should see the graph taking a dip at this point.

3 0
3 years ago
Identify the terminal point for a 60° angle in a unit circle.
Oksana_A [137]

Answer:

it's A

Step-by-step explanation:

i hope this helps :D

4 0
2 years ago
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