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Oxana [17]
2 years ago
11

What is the density of a 12-gram sample of zinc with volume of 8.4 cm3? pls hurry pls

Chemistry
1 answer:
Sindrei [870]2 years ago
8 0

AnswerIm telling your teacher "Ms.Byrd" your in 8th grade and go to berry middle?

Explanation:

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Please can someone help I will mark brainiest!
vazorg [7]

Answer:

2Cl- ⇒ Cl ↓2+ 2e

Explanation: sorry if this is not what you were looking for.

6 0
3 years ago
A hot lump of 36.2 g of iron at an initial temperature of 62.0 °C is placed in 50.0 mL of H2O initially at 25.0 °C and allowed t
Viefleur [7K]
Temperature of 62.0 °C is placed in 50.0 mL of H2O initially at 25.0 °C and allowed to reach thermal equilibrium
7 0
3 years ago
Balance the equation for magnasuin and oxygen to yield magnasuimoxide
Minchanka [31]

Answer:

2Mg + O₂  →  2MgO

Explanation:

Chemical equation:

Mg + O₂  →  MgO

Balanced chemical equation:

2Mg + O₂  →  2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂  →  MgO

Mg = 1         Mg = 1

O = 2           O = 1

Step 2:

2Mg + O₂  →  MgO

Mg = 2         Mg = 1

O = 2           O = 1

Step 3:

2Mg + O₂  →  2MgO

Mg = 2         Mg = 2

O = 2           O = 2

6 0
3 years ago
A standard 1.00 kg mass is to be cut from a bar of steel having an equilateral triangular cross section with sides equal to 2.50
Elden [556K]

Answer:

The section of the bar is 2.92 inches.

Explanation:

Mass of the steel cut ,m = 1.00 kg = 1000 g

Volume of the steel bar = V = Area × height

Height of the of the  section of bar = h

Area of  Equilateral triangular = \frac{\sqrt{3}}{4}a^2

a = 2.50 inches

Cross sectional area of the steel mass = A

A=\frac{\sqrt{3}}{4}(2.50 inches)^2=2.71 inches^2

V = 2.71 inches^2\times h

Density of the steel = d =7.70 g/cm^3

1cm^3 = 0.0610237 inches^3

d=\frac{m}{v}

\frac{7.70 g}{0.0610237 inches^3}=\frac{ 1000 g}{2.71 inches^2\times h}

h=\frac{ 1000 g\times 0.0610237 inches^3}{2.71 inches^2\times 7.70 g}

h = 2.92 inches

The section of the bar is 2.92 inches.

3 0
3 years ago
Fake answers are reported and your account will be banned
Leona [35]

Answer:

BRAINLIEST?

Explanation:

Ammonia is a typical weak base. Ammonia itself obviously doesn't contain hydroxide ions, but it reacts with water to produce ammonium ions and hydroxide ions. My findings said that ammonia is a weak base, potassium hydroxide is a strong base, vinegar is a weak acid and ethyl alcohol is a weak acid.

Vinegar and ethyl alcohol are eliminated as they are acids. The question is on bases.... Potassium hydroxide is a strong base. So we are left with ammonia, being a weak base.

A is your answer

8 0
3 years ago
Read 2 more answers
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