Given: Initial volume of gas= 15.0 L
Pressure=1.50 atm
Temperature=23°C
Use ideal gas equation as follows:
Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature in Kelvin.
First convert the given temperature in Kelvin.
0°C=273.15 K
Thus, 23 °C=296.15 K
Rearranging ideal gas equation to calculate the value of nR as follows:
Now, final pressure is 3.50 atm and temperature is 286°C, converting the temperature into Kelvin,
0°C=273.15 K
Thus, 286 °C=559.15 K
Volume can be calculated using the ideal gas equation as follows:
Putting the value of given pressure and temperature and the above calculated value of nR,
Therefore, volume of at 3.50 atm and 286°C is 12.14 L.
