Your question, I guess, How do vapour and gases differ...
Answer:
1.) Vapour is the changed state of any liquid either due to boiling or evaporation
2.) Vapour are more energetic as they have absorbed the latent heat of vaporization whereas Gases are low in energy because they are already in gaseous form at room temperature.
3.) Vapour have boiling points above room temperature while gases have their boiling point below room temperature.
Answer:
k = 4,92x10⁻³
Explanation:
For the reaction:
AB₂C (g) ⇄ B₂(g) + AC(g)
The equilibrium constant, k is defined as:
![k = \frac{[B_{2}][AC]}{[AB_2C]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5BB_%7B2%7D%5D%5BAC%5D%7D%7B%5BAB_2C%5D%7D)
<em>(1)</em>
Molar concentration of the species are:
[AB₂C]: 0,0840mol / 5L = <em>0,0168M</em>
[B₂]: 0,0350mol / 5L = <em>0,0070M</em>
[AC]: 0,0590mol / 5L = <em>0,0118M</em>
Replacing this values in (1):
![k = \frac{[0,0070][0,0118]}{[0,0168]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5B0%2C0070%5D%5B0%2C0118%5D%7D%7B%5B0%2C0168%5D%7D)
<em>k = 4,92x10⁻³</em>
I hope it helps!
Answer:
The value of Kc is 660 (Option E) is correct
Explanation:
Step 1: Data given
Kp = 27
Temperature = 25.0 °C
Step 2: The balanced equation
2 NO(g) + Br2(g) ⇄ 2 NOBr(g)
Step 3: Calculate Kc
Kp = Kc * (RT)^Δn
⇒ with Kp = 27
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 L*atm/mol*K
⇒ with T = The temperature = 25 °C = 298 K
⇒ Δn = the difference in moles = -1
27 = Kc * (0.08206*298)^-1
Kc = 660
The value of Kc is 660 (Option E) is correct
The correct SI system to use the measuring the mass of a boulder is Kilograms.
During diffusion substances move from the denser medium (meaning where there is more of the substance) to less dense medium (meaning where there is less of the substance).
