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harina [27]
4 years ago
13

Can someone help pleeeeaaassssse quicklyAlso it's 15 points so yeah

Mathematics
1 answer:
kodGreya [7K]4 years ago
8 0

Answer:

D

Step-by-step explanation:

To get from the little triangle to the big one, multiply all the litte one's sides by 3.

So the corresponding side to 4 would be 4 * 3  = 12

The area of a right triangle is 1/2 * b * h

b = 9

h = 12

Area = 1/2 * 9 * 12

Area = 54

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25^(x+2) = (1/5)^(4x)
dangina [55]
The first step for solving this equation is to write 25^{x+2} in exponential form with a base of 5.
5^{2x+4} = ( \frac{1}{5}) ^{4x}
Write ( \frac{1}{5}) ^{4x} in exponential form with a base of 5.
5^{2x+4} = 5^{-4x}
Since the bases on both sides of the equal are the same,, set the exponents equal.
2x + 4 = -4x
Move the constant to the right side of the equation and then change its sign.
2x = -4x - 4
Now move the variable to the left side and change its sign.
2x + 4x = -4
Collect the terms with an x variable.
6x = -4
Lastly,, divide both sides of the equation by 6 to get your final answer.
x = - \frac{2}{3}
Let me know if you have any further questions.
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8 0
3 years ago
What is the simplified form of each expression?<br>3-3: (-2)​
frez [133]

Answer:

9

Step-by-step explanation:

multiply -3 and -2 = 6

6 + 3 = 9

so the answer will be 9

8 0
3 years ago
ellie must mix 6 tablespoons of plant food for every 2 gallons of water. If she has 6 gallons of water, how muck plant food shou
mel-nik [20]

Answer:

Step-by-step explanation:

she need 18 tablespoons of plant food for 6 gallons of water:)

8 0
3 years ago
What if f(0)?<br> 12 only<br> 2 and 3 only<br> -2,-1,1 and 2 only<br> -2,-1,1,2 and 12
Sunny_sXe [5.5K]

Answer:

Helppppppp

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If the 5th term of a geometric progression is 162 and the 8th term is 4374, find the (i) 1st three terms of the sequence; (ii) s
Alona [7]

Answer:

see explanation

Step-by-step explanation:

The nth term of a geometric progression is

a_{n} = a₁r^{n-1}

where a₁  is the first term and r the common ratio

Given a₅ = 162 and a₈ = 4374 , then

a₁r^{4} = 162 → (1)

a₁r^{7} = 4374 → (2)

Divide (2) by (1)

\frac{a_{1}r^{7}  }{a_{1}r^{4}  } = \frac{4374}{162}

r³ = 27

r = \sqrt[3]{27} = 3

Substitute r = 3 into (1) and solve for a₁

a₁(3)^{4} = 162

81a₁ = 162

a₁ = \frac{162}{81} = 2

Then

a₂ = a₁ × 3 = 2 × 3 = 6

a₃ = a₂ × 3 = 6 × 3 = 18

The first 3 terms are 2, 6, 18

(ii)

The sum to n terms of a geometric progression is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1} , then

S_{10} = \frac{2(3^{10}-1) }{3-1}

     = \frac{2(59049-1)}{2}

     = 59049 - 1

     = 59048

   

6 0
3 years ago
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