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3 years ago

9

Gallon of cleaner are on sale for 50% off the regular price of $3.18. a customer buys one gallon and the cashier $5.00 The custo

mer change is

1 answer:

Vera_Pavlovna [14]3 years ago

7 0

50% off $3.18 = 3.18 X .50 = 1.59

3.18 minus discount of 1.59 = 1.59

Now 5.00 - total cost of 1.59 = 3.41 in change

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A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs

LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

$h=\frac{400}{\pi r^2}$

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: $h=\frac{400}{\pi r^2}$

Therefore:

$C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})$

$C(r)=0.12\pi r^2+\frac{24}{r}$

$C(r)=\frac{0.12\pi r^3+24}{r}$

The minimum cost occurs when the derivative of the Cost =0.

$C^{'}(r)=\frac{6\pi r^3-600}{25r^2}$

$6\pi r^3-600=0$

$6\pi r^3=600$

$\pi r^3=100$

$r^3=\frac{100}{\pi}$

$r^3=31.83$

r=3.17 cm

Recall that:

$h=\frac{400}{\pi r^2}$

$h=\frac{400}{\pi *3.17^2}$

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

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You must begin by isolating the x.
1. add -35 to the other side of the equation

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Answer:
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Scale factor:

Explanation:
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113.1in³ should be tge volume

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find the probability of exactly two successes in five trials of a binomial experiment in which the probability of success is 50%

HACTEHA [7]

ANSWER: 31.25%

Explaination:

Suppose (x+y) $(x+y)^{5}$ is the binomial distribution with 5 trials. Given that, probability of exactly two success in five trials of a binomial experiment in which the probability of success is 50%.

So, x = 0.5 and y = 0.5

The term

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Now find the value of this term.

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