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3 years ago

Apply the distributive property to factor out the greatest common factor.8x−20=

Mathematics

1 answer:

RideAnS [48]3 years ago

3 0

4(2x-5)
the answer to the question

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Find the median of this data: 18, 9, 17, 18, 15, 10, 18. If necessary, round to the nearest tenth.

Marta_Voda [28]

9, 10, 15, 17, 18, 18, 18

17

3 0

3 years ago

I need to know what is the chance the driver still got in an accident

Yakvenalex [24]

Answer:

answer is 35

Step-by-step explanation:

5 0

3 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

3 years ago

Your lunch bill for Saturday after noon is $12.19. You leave a 20% tip and are charged 8% sales tax. Your lunch bill for Sunday

m_a_m_a [10]

Answer:

You pay more for your lunch bill on Sunday

Step-by-step explanation:

You pay a total of $15.80 on Saturday and $16.27 on Sunday

7 0

3 years ago

My daugher is trying to <br>Solve -7.8x=-1.56

Hunter-Best [27]

You would just have to isolate for x
so it would simply become
-1.56/-7.8
= 0.2

8 0

4 years ago