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aev [14]
4 years ago
10

`i have a sealed cylinder sitting in my lab that contains 1,000.0 ml of gas. if i compress the cylinder and change the volume to

500.0 ml, keeping the temperature constant, what will i expect to see happen to the pressure?
Physics
1 answer:
marin [14]4 years ago
7 0
Because the temperature remains constant, we can apply Boyle's Law which states that 
pV = constant
where
p = pressure
V = volume

Define the two states of the gas.

State 1
Pressure = p₁
Volume = 1000 ml

State 2
Pressure = p₂
Volume = 500 ml

Apply Boyle's law.
1000p₁ = 500p₂
2 = p₂/p₁

By halving the volume, the pressure doubles.

Answer:
The pressure increases by a factor of 2.

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Bart runs up a 2.91 meters high flight of stairs at a constant speed in 2.15 seconds. If barts mass is 65.9kg determine the work
Tanzania [10]

Answer:

1879.33J

874.1W

Explanation:

Given parameters:

Distance covered  = 2.91m

Time taken  = 2.15s

Mass of Bart = 65.9kg

Unknown:

Work done  = ?

Power rating  = ?

Solution:

Here, the work done is related to the the potential energy in climbing this flight of stairs.

  Work done = Potential energy  = mgH

where m is the mass

           g is the acceleration due to gravity

           H is the height

Work done  = 65.9 x 9.8 x 2.91  = 1879.33J

Power is defined as the rate at which work is being done.

         Power = \frac{Work done }{time taken}

                     = \frac{1879.33}{2.15}

                      = 874.1W

6 0
3 years ago
How are science and technology the same
Ilia_Sergeevich [38]

Answer:

Science is the study of the natural world by collecting data through a systematic process called the scientific method. And technology is where we apply science to create devices that can solve problems and do tasks. Technology is literally the application of science

Explanation:

3 0
3 years ago
as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p
miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

E = (3)(230\ m/s)(0.61\ T)Sin90^o

<u>E = 420.9 N/C</u>

3 0
3 years ago
A current of 0.96 amps flows through a copper wire 0.44 mm in diameter when connected to a potential difference of 15 v. how lon
FinnZ [79.3K]
By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
V=IR
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
R= \frac{V}{I}= \frac{15 V}{0.96 A}=15.6 \Omega

Now we can use the following equation to calculate the length of the wire:
R= \frac{\rho L}{A} (1)
where
\rho is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity \rho=1.68 \cdot 10^{-8} \Omega m. The radius of the wire is half the diameter:
r= \frac{d}{2}= \frac{0.44 mm}{2}=0.22 mm=0.22 \cdot 10^{-3} m
And the cross-sectional area is
A=\pi r^2=\pi (0.22 \cdot 10^{-3}m)^2=1.52 \cdot 10^{-7} m^2

So now we can rearrange eq.(1) to calculate the length of the wire:
L= \frac{RA}{\rho}= \frac{(15.6 \Omega)(1.52 \cdot 10^{-7} m^2)}{1.68 \cdot 10^{-8} \Omega m}=141.1 m
8 0
4 years ago
A ball on the end of a string is revolving at a uniform rate in a vertical circle of radius 97.7 cm. If its speed is 3.74 m/s, a
noname [10]

The tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

<h3>Tension</h3>

A tension is simply referred to as a force along the length of a flexible medium such as strings, cable, ropes etc.

Tension in a string revolving can be determined using the expression;

T = mv² / r

Where m is mass of object, v is velocity and r is radius ( length of string )

Given the data in the question;

  • Mass of ball m = 0.182kg
  • Radius ( length of string ) r = 97.7cm = 0.977m
  • Velocity = 3.74m/s
  • Tension in the string; T = ?

To determine tension in the string, we substitute our given values into the expression above.

T = mv² / r

T = (0.182kg × (3.74m/s)²) / 0.977m

T = (0.182kg × 13.9876m²/s²) / 0.977m

T = (2.5457432kgm²/s²) / 0.977m

T = 2.61kgm/s²

T = 2.61N

Therefore, the tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

Learn more about Tension here: brainly.com/question/14351325

7 0
2 years ago
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