Answer:
option E
Explanation:
given,
diameter = 4 mm
shutter speed = 1/1000 s
diameter of aperture = ?
shutter speed = 1/250 s
exposure time to the shutter time
N is the diameter of the aperture and t is the time of exposure
now,
inserting all the values
N₂² = 4
N₂ = 2 mm
hence , the correct answer is option E
Answer:
The electric potential in volts is 1.618 x 10⁻¹⁷ V
Explanation:
The electric potential, in volts, at point P, can be calculated as follow;
Electric potential is the work done in moving a unit positive charge from infinity to a particular point in the electric field.
Thus, the work done in this process in moving the charge to point p is 101eV.
Convert this Volts = 101 × 1.602 x 10⁻¹⁹ V
= 1.618 x 10⁻¹⁷ V
Therefore, the electric potential in volts is 1.618 x 10⁻¹⁷ V
Answer:
So capacitance is charge divided by voltage and we can multiply both sides by V to solve for Q. So Q—the charge stored in the capacitor—is the capacitance multiplied by the voltage. So it's 180 times 10 to the minus 6 farads times 120 volts which is 0.0216 coulombs.
Explanation:
Answer:
by using graphical meythod
