<span>As the angle has been measured from north, the north component should be calculated with cosine and the west component should be calculated with sine:
Vn = 835km/h*cos(41.5) =625 km/h
Vw = 835km/h*sin(41.5) =553 km/h
In order to calculate the distance travelled after 2.5 hours, we should use the uniform linear movement formula:
d=v*t
total distance (modulus of the distance)= 835km/h*2.5h=2088 km
Or we can calculate each component (north and west):
dn=625 km/h*2.5h=1563 km
dw=553 km/h*2.5h=1383 km
</span>
Explanation:
Total displacement =30+20=50 Km
Average velocity =displacement /time
V=50/1.5=33.33km/hr
The flea jumps at high velocity, reaches zero velocity at the maximum height 21.1 cm before starting to fall. Solve for initial velocity given final velocity is zero.
since time is not given, use the equation:
v^2 = u^2 + 2as
convert gravity or displacement to have same units. 9.8 m/s = 980 cm/s
0 = u^2 + 2(-980)(21.1)
41356 = u^2
sqrt(41356) = u
203.4 cm/s = u
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So 
We have to find the speed of the wave in the string
Speed is equal to 
So speed of the wave in the string will be 3.2 m/sec
Answer:
32.9166667 m / s^2
Explanation:
s = 4.25km (1000m / 1km)
= 4250m
u = 20m/s
delta T = 20min (60sec / 1min)
= 1200s
Use formula s = ut + (1/2)at^2
4250m = 20m/s * 1200s + (1/2)a*1200s^2
Rearrange it to find a
a = (s-ut) / (1/2 * t^2)
a = (4250m - 20m/s*1200s) / (1/2 * 1200s^2)
a = -32.9166667 m / s^2
